The number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
<h3>Rental cost</h3>
Let
Company A:
90 + 0.20x
Company B:
20 + 0.70x
90 + 0.20x = 20 + 0.70x
90 - 20 = 0.70x - 0.20x
70 = 0.50x
- Divide both sides by 0.50
x = 70/0.50
x = 140 miles
Therefore, the number of miles in a day at which the rental costs for Company A and Company B are the same is 140 miles
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As an integer and a raitonal number as well as a real number.
9514 1404 393
Answer:
0.344
Step-by-step explanation:
There are 20C10 = 184,756 ways to choose 10 problems at random from a list of 20.
There are 10C5 = 252 ways to choose 5 of the 10 algebra problems, and the same number of ways to choose 5 of the 10 geometry problems. Then there are 252² = 63,504 ways to choose 5 problems each of algebra and geometry.
The probability of choosing 5 problems in each category is ...
63504/184756 ≈ 0.344
Hi,
o) 357 - 486 = -129
f) 4572 + 609 = 5181
b) -12 - 31 = -43
n) - 15 + 8 = -7
Hope this helps.
r3t40
