We need (x-h)^2 + (y-k)^2 = r^2
h = 4, k = 0 and r = 2/3
Take it from here.
Perpendicular lines have slopes that multiply to get -1
y=mx+b is the slope intercept equation
m=slope
so get into y=mx+b form
-x+2y=4
solve for y
add x both sides
2y=x+4
divide by 2 both sides
y=(1/2)x+2
the slope is 1/2
perppendicular line slope multiplies to -1
1/2 times what=-1
times 2/1 both sides
what=-2/1=-2
y=-2x+b
find b
we are given a point is (-2,1)
when x=-2, y=1
1=-2(-2)+b
1=4+b
minus 3 both sides
-3=b
so the equation is
y=-2x-3
your teacher might want it in standard form (ax+by=c) so
add 2x both sides
2x+y=-3 is an equation
so y=-2x-3 is correct (slope intercept form)
2x+y=-3 is also correct (standard form)
The answer is B: <span> a^12/b^6
Proof:
Simplify the following:
(a^4/b^2)^3
Multiply each exponent in a^4/b^2 by 3:
(a^(3×4))/((b^2)^3)
3×4 = 12:
a^12/(b^2)^3
Multiply exponents. (b^2)^3 = b^(2×3):
a^12/b^(2×3)
2×3 = 6:
Answer: a^12/b^6</span>
Answer:
Concept: Geometric Identities
- We want BC
- We will use geometric identities to get our value
- We have BA and AC and angle !A
- Hence arccos(89)= 21/x
- Hence X=25 km B
Tossing a coin.
Let Heads be represented as H
Let Tail be represented as T
When a coin is tossed, then there are two possible outcomes.
We can either get a tail or a heads.
It can be represented as = { H } or { T }
If a coin is tossed then the probability of getting a head is 50% and the probability of getting a tail is 50%
