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BabaBlast [244]

3 years ago

5

The list shows the scores posted by a professional golfer for his last ten rounds of golf. , Scores for 18 Holes of Golf 67 68 6

9 69 69 71 71 72 73 75 Question What is the median of the data set? ( NEED HELP ASAP)

1 answer:

Arturiano [62]3 years ago

3 0

Answer:

The correct answer is 70

Step-by-step explanation:

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Find the approximate circumference, in terms of π, of chicken pie that had a radius of 3.25 inches.

nirvana33 [79]

Answer:

B

Step-by-step explanation:

I Had this

3 0

3 years ago

mei has 15 oranges,9 peaches, and 18 pears. she wants to put all of the fruit into decorative baskets, what's the greats number

pashok25 [27]

Answer:

15,9,8 can be divided by 3

so, the greatest number of fruit in each basket is 3 Step-by-step explanation:

6 0

3 years ago

explain why the exponents cannot be addded in the proududct 12 to the third power 11 to the third power

Oksi-84 [34.3K]

12 ^3 and 11^3 haven't got the same base so the rules of exponents do not apply.

Bases have to be the same:- for example 12^3 * 12*3 = 12 ^(3+3) = 12^6

5 0

3 years ago

Find the P-value for a test of the claim that more than 60% of the people following a particular diet will experience increased

lina2011 [118]

Answer:

The p-value of the test is 0.0207.

Step-by-step explanation:

Test of the claim that more than 60% of the people following a particular diet will experience increased energy (H1: p > 0.6).

The null hypothesis is:

$H_0: p = 0.6$

The alternate hypothesis is:

$H_1: p > 0.6$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.6 is tested at the null hypothesis:

This means that $\mu = 0.6, \sigma = \sqrt{0.6*0.4}$

Of 100 randomly selected subjects who followed the diet, 70 noticed an increase in their energy level.

This means that $n = 100, X = \frac{70}{100} = 0.7$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.7 - 0.6}{\frac{\\sqrt{0.6*0.4}}{\sqrt{100}}}$

$z = 2.04$

P-value of the test:

The p-value of the test is the probability of finding a sample proportion of at least 0.7, which is 1 subtracted by the p-value of z = 2.04.

Looking at the z-table, z = 2.04 has a p-value of 0.9793

1 - 0.9793 = 0.0207

The p-value of the test is 0.0207.

4 0

3 years ago

A dishonest shopkeeper has two false balances. One balance weighs 10% more while

sleet_krkn [62]

Answer:

Shopkeepers gain just by weighing is 22.22%

Step-by-step explanation:

Explanation:

Assume that the shopkeeper bought x units of goods i.e. actual weight of goods.

As the balance used to buy goods weighs 10% more, he actually bought x×110100=1.1x weight units i.e. although the shopkeeper paid for x units, he actually bought 1.1x units by weight.

Now he has 1.1x units of goods, but for selling he uses another balance, which actually measures 10% less i.e. 1−0.10=0.9 units for each unit weight of goods sold.

So while selling 1.1x becomes 1.1x0.90=1.2222... units.

Hence, shopkeepers gain just by weighing is 22.22%

5 0

3 years ago