All categories

3 years ago

explain why the exponents cannot be addded in the proududct 12 to the third power 11 to the third power

1 answer:

5 0

12 ^3 and 11^3 haven't got the same base so the rules of exponents do not apply.

Bases have to be the same:- for example 12^3 * 12*3 = 12 ^(3+3) = 12^6

You might be interested in

Help me please I don’t know how to do it

Rasek [7]

Answer:

ask your teacher for help.

Step-by-step explanation:

4 0

1 year ago

If y varies directly with x, and y is 6

Dvinal [7]

Answer:

Step-by-step explanation:

see the pic for the steps

6 0

3 years ago

Please help me ill mark you brainliest and please show your work :)

Nana76 [90]

Answer:

Step-by-step explanation:

Multiply both sides of the equation by 8/5.

4x-16=32

Move 16 to the other side

4x=32+16

add numbers on the right side

4x=48

divide both sides by 4

x=12

7 0

2 years ago

Solve for x and show work. Round to the tenths place.

Dafna1 [17]

This is your answer!

5 0

2 years ago

You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that t

icang [17]

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

$P(H)=\frac{13}{52}=0.25$

Compute the probability of selecting a Spade second as follows:

$P(S)=\frac{13}{51}=0.255$

Since the two cards are selected without replacement the second draw is independent of the other.

Then the probability that the first card is a Heart and the second card is a Spade is:

$P(1st\ H\cap 2nd\ S)=P(H)\times P(S)$

$=0.25\times 0.255\\=0.06375\\\approx 0.064$

Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

4 0

3 years ago