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Sati [7]
3 years ago
8

Which graph represents a nonlinear function?​

Mathematics
2 answers:
Lubov Fominskaja [6]3 years ago
8 0
It’s the second one, nonlinear functions are curved, linear functions are straight.
Genrish500 [490]3 years ago
5 0

Answer:

It's the second one :) I think?

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What is the area of a semicircle with a diameter of 10 cm?
Irina18 [472]

Answer:

<h2>39.27 cm²</h2><h2 />

Step-by-step explanation:

area of semi circle = π r² / 2

where r = 10/2 = 5 cm

area = π (5)² / 2

        = 39.27 cm²

7 0
3 years ago
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Is it possible that you could get an answer that checks and works in one equation and does not work in the other equation?
Novay_Z [31]

Answer:I’m not sure

Step-by-step explanation:

4 0
3 years ago
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What is the following​
Stella [2.4K]

Answer:

what is it you just said What is the following​?

Step-by-step explanation:

3 0
3 years ago
How do you do 5ln x= 35....?
sergejj [24]

That's going to depend a lot on what you want to "do" to it.

I'm going to assume that you want to find a number for 'x' that makes
the whole equation a true statement.  Here's how I would do it:

                                  <u> 5 ln(x) = 35</u>

Divide each side by  5:  ln(x) = 35/5
                                      ln(x)  =  7

Raise 'e' to the power of each side:    e^[ ln(x) ] = e⁷

But  e^[ ln(x) ] is just 'x'.  So x = e⁷ = <em>1,096.633...</em> (rounded)

That's the only number you can write in place of 'x'
and make the original equation true.


5 0
3 years ago
Consider 3 trials, each having the same probability of successes. Let X denote the total number of successes in these trials.
Mariulka [41]

Since each trial has the same probability of success, 

Let, <span><span><span>Xi</span>=1</span></span> if the <span><span>i<span>th</span></span></span> trial is a success (<span>0</span> otherwise). Then, <span><span>X=<span>∑3<span>i=1</span></span><span>Xi</span></span><span>X=<span>∑<span>i=1</span>3</span><span>Xi</span></span></span>, 

and <span><span>E[X]=E[<span>∑3<span>i=1</span></span><span>Xi</span>]=<span>∑3<span>i=1</span></span>E[<span>Xi</span>]=<span>∑3<span>i=1</span></span>p=3p=1.8</span><span>E[X]=E[<span>∑<span>i=1</span>3</span><span>Xi</span>]=<span>∑<span>i=1</span>3</span>E[<span>Xi</span>]=<span>∑<span>i=1</span>3</span>p=3p=1.8</span></span>

So, <span><span>p=0.6</span><span>p=0.6</span></span>, and <span><span>P{X=3}=<span>0.63</span></span><span>P{X=3}=<span>0.63</span></span></span>

I thought what I did was sound, but the textbook says the answer to (a) is <span>0.60.6</span> and (b) is <span>00</span>.

Their reasoning (for (a)) is as follows:

3 0
3 years ago
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