A line segment has endpoints at (3, 2) and (2, –3). Which reflection will produce an image with endpoints at (3, –2) and (2, 3)?
2 answers:
Answer:
Reflection over x axis
Step-by-step explanation:
Given : A line segment has endpoints at (3, 2) and (2, –3).
To Find: Which reflection will produce an image with endpoints at (3, –2) and (2, 3)?
Solution:
Rule of reflection over x axis
(x,y)→(x,-y)
Point (3,2) when reflected over x axis:
(3,2)→(3,-2) (using rule of reflection over x axis)
Point (2, –3)when reflected over x axis
(2,-3)→(2,-(-3))→(2,3) (using rule of reflection over x axis)
So, (2,-3)→(2,3)
Thus we can see that a line segment has endpoints at (3, 2) and (2, –3) when reflected over x axis then an image with endpoints at (3, –2) and (2, 3) will be produced.
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Step-by-step explanation:
This is a linear equation in slope intercept form which is
where m is the slope and b is the y intercept.
The equation
Has a slope of -1/3 so this means that the slope will be decreasing. A negative linear equation increases as we go left. and decreases as we go right. The y intercept is 2. So this means the graph must pass through (0,2) and when x=0, y must be 2.
In other words, look for a line that the y values increase as we go left and decrease we go right. Also look for a point (0,2) and make sure the graph pass through it.