Please help me i’ll give points

A corporate bond has a coupon rate of 5.5 percent, a $1,000 face value, and matures three years from today. The corporation is i

melomori [17]

Answer:

$= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000 }{(1+\frac{15}{100})^3 }$

$=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}$

$=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76$

Step-by-step explanation:

= (probability of entire face value paid*face value+probability of entire face value not paid*percent of face value paid*face value)/(1+discount rate)^years to maturity

probability of entire face value paid = 75%

face value = 1000

probability of entire face value not paid = 25%

percent of face value paid= 60%

discount rate = 15%

years to maturity = 3

$= \frac{\frac{75}{100}\times 1000 + \frac{25}{100} \times \frac{60}{100}\times 1000 }{(1+\frac{15}{100})^3 }$

$=\frac{0.75\times 1000 + 0.25\times 0.60 \times 1000}{(1+0.15)^3}$

$=\frac{750+0.25\times 0.60\times 1000}{1.15^3} \\\\=\frac{750+150}{1.520875} =\frac{900}{1.520875} \\\\=591.76$

6 0

2 years ago

Check the true statements below:

valentinak56 [21]

Answer:

a) False

b) False

c) True

d) False

e) False

Step-by-step explanation:

a. A single vector by itself is linearly dependent. False

If v = 0 then the only scalar c such that cv = 0 is c = 0. Hence, 1vl is linearly independent. A set consisting of a single vector v is linearly dependent if and only if v = 0. Therefore, only a single zero vector is linearly dependent, while any set consisting of a single nonzero vector is linearly independent.

b. If H= Span{b1,....bp}, then {b1,...bp} is a basis for H. False

A sets forms a basis for vector space, only if it is linearly independent and spans the space. The fact that it is a spanning set alone is not sufficient enough to form a basis.

c. The columns of an invertible n × n matrix form a basis for Rⁿ. True

If a matrix is invertible, then its columns are linearly independent and every row has a pivot element. The columns, can therefore, form a basis for Rⁿ.

d. In some cases, the linear dependence relations among the columns of a matrix can be affected by certain elementary row operations on the matrix. False

Row operations can not affect linear dependence among the columns of a matrix.

e. A basis is a spanning set that is as large as possible. False

A basis is not a large spanning set. A basis is the smallest spanning set.

3 0

2 years ago

Find the HCF of<br> x^2y and x

3241004551 [841]

The highest common factor of $x^2 y$ and $x$ is $\boxed{x}$

6 0

1 year ago

Word search

Shkiper50 [21]

Answer:

A Is congruent to A, B Is congruent to B, C Is congruent to C ... Each triangle is an isosceles triangle. ... B G and P X are labeled with a double tick mark The angle L B G and angle F P X are ... line segmentSection FormulasimilarmidpointSimilarity Theoremdilationcenter of ...

Step-by-step explanation:

onverse of the Triangle Proportionality Theorem dilation. Converse of the Angle Bisector Theorem scale factor. The Midpoint ...

5 0

2 years ago

You are designing a wall Mural that will be composed of squares of different sizes. One of the requirements of your design is th

Oxana [17]

Answer:

1. Area of a square = (x^2)^2 = x^4

(each side is x^2, area of a square = side^2

so (x^2)(x^2) = x^4 )

2. when x = 5

area = 5^4 = 625

3. when x = 10

area = 10^4 = 10000

Step-by-step explanation:

Hope its right!

6 0

3 years ago