11. Find the roots of x2 - 8x + 4 = 0, in simplest radical form.

Please help me !!!!!!!!!!!!!!!!

Nutka1998 [239]

Answer: x=-10, y=13

Step-by-step explanation:

$-3x+2y=56\\-5x-2y=24$

+2y-2y = 0, eliminating y is much easier. So -3x-5x = -8x and 56+24 = 80

$-8x=80\\x=-10$

Substitute x in any equations but only 1 equation (Don't substitute in both equations.)

For me, I'd substitute x in -3x+2y=50

$-3(-10)+2y=56\\30+2y=56\\2y=56-30\\2y=26\\y=13$

So the answer is x = -10, y = 13

5 0

2 years ago

Efectuati impartirea 12xy:3x

adelina 88 [10]

In this question , we have to simplify the given ratio, which is

12xy:3x

First we have to see which factor is common in numerator and denominator,

We can write 12 as 3 times 4, that is

$3*4x*y :3x$

So the common factor is 3x.

In the next step, we cancel out 3x

$4y:1$

And that's the required simplified form .

7 0

3 years ago

Read 2 more answers

B is the midpoint of AC. If Ab= x +5 and BC = 2x-11, find the measure of Ab.

LuckyWell [14K]

__________________________

Measurement of "AC" :

(x + 5) + (2x <span>− 11) ;
________________________

Find the measurement of "AB" [which is: "(x+5)" ]:
______________________________________________
First, simplify to find the measurement of "AC" :
________________________________________
</span>(x + 5) + (2x − 11) ;

= (x + 5) + 1(2x − 11) ;

= x + 5 + 2x − 11 ;

→ Combine the "like terms" ;

x + 2x = 3x ;

5 − 11 = - 6 ;
______________
to get: 3x − 6 ;
_______________
So, (x + 5) + (2x − 11) = 3x − 6 ;
_______________________________
Solve for: "(x + 5)"
_______________________________

We have:
_______________________________

(x + 5) + (2x − 11) = 3x − 6 ;

Subtract: "(2x − 11)" ; from EACH SIDE of the equation ;
to isolate "(x + 5)" on one side of the equation;
and to solve for "(x + 5)" ;
________________________________________________________
→ (x + 5) + (2x − 11) − (2x − 11) = (3x − 6) − (2x − 11) ;

→ (x + 5) = (3x − 6) − (2x − 11) ;
_________________________________________________
Note: Simplify: "(3x − 6) − (2x − 11)" ;

→ (3x − 6) − (2x − 11) ;

= (3x − 6) − 1(2x − 11) ;

= 3x − 6 − 2x + 11 ;
__________________________
→ Combine the "like terms" :
_____________________________
+3x − 2x = 1x = x ;

-6 + 11 = 5 ;
_____________________________
To get: x + 5 ;

So we have:
______________________________
x + 5 = x + 5 ;
______________________________

So, x = all real numbers.

x = <span>ℝ </span>

4 0

2 years ago

-5y-3+6y=15 How do I solve it?

juin [17]

Combine like terms. 6y-5y is 1y, which simplifies to y. the equation is y-3=15. y=18 is the answer because you add 3 to 15

5 0

2 years ago

How to work it out logically? Question a !!!

Arturiano [62]

Answer:

Fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

Step-by-step explanation:

Given the figure with dimensions. we have to find the area of given figure.

Area of figure=ar(1)+ar(2)+ar(3)

Area of region 1 = ar(ANGI)+ar(AIB)

$=L\times B+\frac{1}{2}\times base\times height\\\\=[1500\times (5000-2000-1500)]+\frac{1}{2}\times (3000-1500)\times (5000-2000-1500)\\\\=3375000m^2=337.5ha$

Area of region 2 = ar(DHBC)

$=2000\times1500\\\\=3000000m^2=300ha$

Area of region 3 = ar(GFEH)

$(2000+1500)\times 1000\\\\=3500000m^2=350ha$

Hence, Area of figure=ar(1)+ar(2)+ar(3)=337.5ha+300ha+350ha

=987.5 ha

Now, we have to do straight-line fencing such that area become half and cost of fencing is minimum.

Let the fencing be done through x m downward from B which divides the two into equal area.

⇒ Area of upper part above fencing=Area of lower part below fencing

⇒ $ar(ANGB)+ar(GKLB)=ar(KLCM)+ar(MDCF)\\\\337500+3000x=(3500-x)\times 1000+2000(1500-x)\\\\3375000+3000x=3500000-1000x+3000000-2000x\\\\6000x=315000\\\\x=\frac{315000}{6000}=520.8m$

Hence, fencing is done along KL which is (1500+520.8=2020.8 m) from the top left corner and divides the property into half.

7 0

2 years ago

Read 2 more answers