1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nadusha1986 [10]
3 years ago
11

4) An arithmetic sequence has a 7th term of 54 and a 13th term of 94. Find the common difference

Mathematics
1 answer:
san4es73 [151]3 years ago
6 0

Answer:

20/3

Step-by-step explanation:

Every nth term takes the form of  a + n*d, where a is the first  term.

So 7th term = (54 = a + 7d), 13th term = (94 = a + 13d).

equate them both:

94 - 13d = 54 - 7d

40 = 6d

d = 40/6

You might be interested in
4(ax+3) - 3ax = 25 + 3a
FrozenT [24]
Let's simplify first:

4ax+12-3ax=25+3a

ax+12=25+3a

ax-3a=25-12

a(x-3)=13

That is how far you can take it, unless there were some additional information for this question.
5 0
4 years ago
Solve this simultaneous equation by method of elimination
lawyer [7]

Answer:

y

=

−

2

x

3

+

1

3

y

=

−

3

x

5

+

1

5

Step-by-step explanation:

7 0
3 years ago
(16 POINTS) (EXPLAIN ANSWER!!)
MAVERICK [17]

Answer:

Step-by-step explanation:

(probability of the first event) x (probability of the second event)

male                    community college

84/164                         93/164

mutiply the two together 1953/6724 or 29%

               

5 0
4 years ago
A substance with a half life is decaying exponentially. If there are initially 12 grams of the substance and after 70 minutes th
77julia77 [94]

Answer: 233 min

Step-by-step explanation:

This problem can be solved by the following equation:

A=A_{o} e^{-kt}  (1)

Where:

A=7 g is the quantity left after time t

A_{o}=12 g is the initial quantity

t=70 min is the time elapsed

k is the constant of decay for the material

So, firstly we need to find the value of k from (1) in order to move to the next part of the problem:

\frac{A}{A_{o}}=e^{-kt}  (2)

Applying natural logarithm on both sides of the equation:

ln(\frac{A}{A_{o}})=ln(e^{-kt})  (3)

ln(\frac{A}{A_{o}})=-kt  (4)

k=-\frac{ln(\frac{A}{A_{o}})}{t}  (5)

k=-\frac{ln(\frac{7 g}{12 g})}{70 min}  (6)

k=0.00769995 min^{-1}  (7)  Now that we have the value of k we can solve the other part of this problem: Find the time t for A=2 g.

In this case we need to isolate t from (1):

t=-\frac{ln(\frac{A}{A_{o}})}{k}  (8)

t=-\frac{ln(\frac{2 g}{12 g})}{0.00769995 min^{-1}}  (9)

Finally:

t=232.697 min \approx 233 min

5 0
3 years ago
Eric made two investments:
klemol [59]

Answer:10

Step-by-step explanation:

Notice that investment Q’s value grows linearly while investment R’s value grows exponentially. In conclusion, investment R’s value will first exceed investment Q’s value in year number 10

3 0
3 years ago
Read 2 more answers
Other questions:
  • Please help I'am lost on these two thank you
    7·2 answers
  • Find the perimeter of the rectangle in yards​
    11·2 answers
  • Complete parts (a) and (b) using the probability distribution below.
    12·1 answer
  • What is the area, in square inches, of the figure shown here? A parallelogram with a height of 3 inches is shown. The height of
    5·2 answers
  • There are 24 students in mr bobs math class 5/8 of these students earned an a on the geometry assessment how many students earne
    9·1 answer
  • What is the solution to this equation? <br><br> 3x + x - 13 + 4 - 6x = 12
    7·2 answers
  • suppose 7,330 dollars is invested at 14.8% per annum for 10 years compounded monthly, how many dollars will be earned in interes
    11·1 answer
  • Solve for x!!!! (see attached picture) HELP!!!
    5·1 answer
  • In a survey of 2,300 people who owned a certain type of​ car, 1,150 said they would buy that type of car again. What percent of
    11·1 answer
  • (x^3+2)and (6x^3+y+x)
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!