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valentina_108 [34]
2 years ago
6

A set of numbers satisfies Benford’s Law if the probability of a number starting with digit d is P(d) = log(d + 1) – log(d).

Mathematics
2 answers:
irakobra [83]2 years ago
8 0

Interpreting the graph and the situation, it is found that the values of d that can be included in the solution set are 1 and 4.

----------------------

  • According to Benford's law, the probability of a number starting with digit is d is:

P(d) = \log{(d + 1}} - \log{d}

  • A number can start with 10 possible digits, ranging from 1 to 9, which are all integer digits.
  • Thus, d can only assume integer digits.
  • In the graph, the solution is d < 5.
  • The integer options for values of d are 1 and 4.
  • For the other options that are less than 5, they are not integers, so d cannot assume those values.

A similar problem is given at brainly.com/question/16764162

Bogdan [553]2 years ago
3 0

Answer:

Answer is choice B & E .  

Choice B is 1

Choice E is 4

Step-by-step explanation:

correct on edg

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The answer is six feet
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oliver tries to cut a piece of metal 30 centimeters long the metal ends up being 29.4 centimeters long what is the percent error
Aleks04 [339]

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I'd say its 1.02% but don't quote me on that

Step-by-step explanation:

6 0
3 years ago
Simplify: -(16 - 5x) 5×-16/ 5× + 16 / -5×-16/ -5 + 16​
bulgar [2K]

Answer:

(16 (1280 x - 4071))/25

Step-by-step explanation:

Simplify the following:

16 - (-16 (-16)×5×16 (16 - 5 x))/(5 (-5) (-5))

Hint: | Express 16/(-5)×(-16)/(-5) as a single fraction.

16/(-5)×(-16)/(-5) = (16 (-16))/(-5 (-5)):

-(-16×5×(-16×16)/(-5 (-5)) (16 - 5 x))/5 + 16

Hint: | Express 5×(-16)/5×(16 (-16))/(-5 (-5)) as a single fraction.

5×(-16)/5×(16 (-16))/(-5 (-5)) = (16 (-16) 5 (-16))/(-5 (-5) 5):

16 - (-16 (-16) 16×5)/(-5 (-5) 5) (16 - 5 x)

Hint: | Multiply 16 and -16 together.

16 (-16) = -256:

-(-16-256×5 (16 - 5 x))/(-5 (-5) 5) + 16

Hint: | Multiply -256 and 5 together.

-256×5 = -1280:

-(-16-1280 (16 - 5 x))/(-5 (-5) 5) + 16

Hint: | Multiply -1280 and -16 together.

-1280 (-16) = 20480:

16 - (20480 (16 - 5 x))/(-5 (-5) 5)

Hint: | In 20480/(-5 (-5) 5), divide 20480 in the numerator by 5 in the denominator.

5 | | 4 | 0 | 9 | 6

| 2 | 0 | 4 | 8 | 0

- | 2 | 0 | | |  

| | | 4 | |  

| | - | 0 | |  

| | | 4 | 8 |  

| | - | 4 | 5 |  

| | | | 3 | 0

| | | - | 3 | 0

| | | | | 0:

16 - (4096 (16 - 5 x))/(-5 (-5))

Hint: | Multiply -5 and -5 together.

-5 (-5) = 25:

16 - (4096 (16 - 5 x))/25

Hint: | Put the fractions in 16 - ((16 - 5 x)×4096)/25 over a common denominator.

Put each term in 16 - ((16 - 5 x)×4096)/25 over the common denominator 25: 16 - ((16 - 5 x)×4096)/25 = 400/25 - (4096 (16 - 5 x))/25:

400/25 - (4096 (16 - 5 x))/25

Hint: | Combine 400/25 - (4096 (16 - 5 x))/25 into a single fraction.

400/25 - (4096 (16 - 5 x))/25 = (400 - 4096 (16 - 5 x))/25:

(400 - 4096 (16 - 5 x))/25

Hint: | Distribute -4096 over 16 - 5 x.

-4096 (16 - 5 x) = 20480 x - 65536:

(20480 x - 65536 + 400)/25

Hint: | Group like terms in 20480 x - 65536 + 400.

Grouping like terms, 20480 x - 65536 + 400 = 20480 x + (400 - 65536):

(20480 x + (400 - 65536))/25

Hint: | Evaluate 400 - 65536.

400 - 65536 = -65136:

(20480 x + -65136)/25

Hint: | Factor out the greatest common divisor of the coefficients of 20480 x - 65136.

Factor 16 out of 20480 x - 65136:

Answer: (16 (1280 x - 4071))/25

3 0
3 years ago
G = {(5,3), (2, 3), (6,4)} Is G^-1 a function and why?
sleet_krkn [62]

Answer:

The inverse relation G^(-1) is not a function. Why not? Because the y value y = 3 is paired up with more than one x value (x = 5, x = 2). The inverse relation G^(-1) is the set shown below

{(3,5), (3,2), (4,6)}

All I've done is swap the (x,y) values for each ordered pair to form the inverse relation. As you can see, x = 3 leads to multiple y value outputs which is why this relation is not a function. So in short, the answer is choice C. To have the inverse relation be a function, each value in the original domain must map to exactly one value in the range only. However that doesn't happen as the domain values map to an overlapping y value (y = 3).

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3 years ago
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Forgive me if I’m wrong. 25?
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3 years ago
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