First you bring the 9 over with the seven
![-2= \sqrt[3]{x+9}](https://tex.z-dn.net/?f=-2%3D%20%5Csqrt%5B3%5D%7Bx%2B9%7D%20)
Now cube both sides

Finally subtract 9 over and get

Check
![7=9+ \sqrt[3]{-17+9}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-17%2B9%7D%20)
![7=9+ \sqrt[3]{-8}](https://tex.z-dn.net/?f=7%3D9%2B%20%5Csqrt%5B3%5D%7B-8%7D%20)

7=7
Answer:
350
Step-by-step explanation:
100% - 36% = 64% (we first find out the remaining percentage)
Now we know there are 98 more chocolate tarts than strawberry tarts. We have to find out that percentage.
So, 64% - 36% = 28%
So 98 of the chocolate tarts make up 28%
x --------> 100%
98 --------> 28%
Just follow the percentage formula.
98 * 100 = 9800
9800/28 = 350
Answer:
No
Step-by-step explanation:
The variables are different in both problems. In 2×+7=27, it's 10, while in the other problem, it's 9.
27 doesn't equal 28.
If x=n then it would have 2 solutions because it would be x^2 = c which has a positive and negative solution but idk if that is what you are asking for