This requires us to find the number of permutations of 6 different bands taken 2 at a time:
All these cases represent experiments whose outcomes are all equaly likely. What we mean is that the cards have all the same probability of being dealt (1/52), and all the spaces of the spinner have the same probability of being landed into (1/5).
These probabilities are computed as 1 over all the possible outcomes.
(a) If you want a heart card and a five, you want the 5 of hearts. So, only one card would satisfy your request, and thus you have probability 1/52 of dealing the 5 of hearts.

(b) There are four 10s and four Jacks in the deck, so 8 cards satisfy your request. With probability 8/52, you'll be dealt a Jack or a 10.

(c) You have two "good" outcomes out of 5, so your probability is 2/5.

Answer:
6? i hope this helps some! :)
Step-by-step explanation:
each has 6 in between the number
5 or 6 p there is a possibility of there being 6
7 or 8 there is at least 6 in this cup
6 or 7 there is at least 6 in this cup
7 or 5 there is a possibility of there being 6
I believe it’s m=3 b=4 I don’t understand really so I think this is my answer
<span>Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively.
x * (x+1) = (x+2) * (x+3) - 38
x^2 + x = x^2 + 5x +6-38
x^2 + x = x^2 + 5x - 32
-4x = -32
x=8
The four numbers are 8, 9, 10, and 11
check solution: 8*9=10*11-38
72=110-38
72=72</span>