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Mathematics

1 answer:

sattari [20]3 years ago

4 0

Answer:

Step-by-step explanation:

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Which of the following is equal to 7^1/3?<br> O A. 3v7<br> B. V7.3<br> C. 7^3<br> D.v7

Shkiper50 [21]

Step-by-step explanation:

what does the ^ stand for? what number does it represent?

7 0

3 years ago

Fine the equation of the line: slope = -2 y-intercept= 5

soldi70 [24.7K]

Using the y=mx+b format
M= slope
B= y-intercept
All you need to do, since both m and b are given us to plug them in! You should commit “y=mx+b” to memory, it’ll help you a ton!
y = -2x+5

3 0

2 years ago

Please help?!’ answerr

Ugo [173]

Answer:

The choice Draw 2

Step-by-step explanation:

$3(8 - 4x) < 6(x - 5) \\ 24 - 12x < 6x - 30 \\ 24- 12x + 12x < 6x + 12x - 30 \\ 24 < 18x - 30 \\ 24 + 30 < 18x - 30 + 30 \\ 54 < 18x \\ 54 \div 18 < 18x \div 18 \\ 3 < x \\ x > 3$

I hope I helped you^_^

6 0

3 years ago

Find the radius of convergence, r, of the series. ∞ xn 2n − 1 n = 1 r = 1 find the interval, i, of convergence of the series. (e

Bingel [31]

Assuming the series is

$\displaystyle\sum_{n\ge1}\frac{x^n}{2n-1}$

The series will converge if

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|$

We have

$\displaystyle\lim_{n\to\infty}\left|\frac{\frac{x^{n+1}}{2(n+1)-1}}{\frac{x^n}{2n-1}}\right|=|x|\lim_{n\to\infty}\frac{\frac1{2n+1}}{\frac1{2n-1}}=|x|-\lim_{n\to\infty}\frac{2n-1}{2n+1}=|x|$

So the series will certainly converge if $-1$ , but we also need to check the endpoints of the interval.

If $x=1$ , then the series is a scaled harmonic series, which we know diverges.

On the other hand, if $x=-1$ , by the alternating series test we can show that the series converges, since

$\left|\dfrac{(-1)^n}{2n-1}\right|=\dfrac1{2n-1}\to0$

and is strictly decreasing.

So, the interval of convergence for the series is $-1\le x$ .

6 0

3 years ago

A light bulb consumes 1440 watt hours per day. How long does it take to consume 4680 watt hours?

Lisa [10]

3.25 hours you take 4680÷1440 = 3.25

8 0

3 years ago