A - bi would be the other complex zero.
When you take the sqrt when solving an equation you get a + and - solution.
So to start off here is the question being asked:
<span>81+<span>7x</span></span>=<span>81
</span>The first thing we are going to do is s<span>implify both sides of the equation:
</span><span><span>7x</span>+81</span>=<span>81
</span>Second thing to do is s<span>ubtract 81 from both sides so:
</span><span><span><span>7x</span>+81</span>−81</span>=<span>81−<span>81
</span></span>The final thing to do is d<span>ivide both sides by 7:
</span><span><span>7x/</span>7</span>=<span>0/<span>7
The final answer is:
x=0
I hope this helps! :)</span></span>
The number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
<h3>How to determine the number of real zeros?</h3>
The equation of the function is given as:
Expand the function
Reorder the terms
Factor the expression
Factor out x -1
Expand
Factorize
](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%5Bx%28x%20%2B%203%29%20%2B%202%28x%20%2B%203%29%5D%28x%20-%201%29)
Factor out x + 2
The function has been completely factored and it has 3 linear factors
Hence, the number of real zeros of the function f(x) = x3 + 4x2 + x − 6 is 3
Read more about functions at:
brainly.com/question/7784687
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The mode's of this set of data are 1,2, and 4.
