Hello! To solve this question, you'll need to set up a ratio to represent this problem. If there are 6 people who have flu-like systems for every 1 person who has the flu, the ratio would be 6:1. Use this ratio to find the number of patients with only flu-like symptoms.
6 (flu-like symptoms) : 1 (flu)
12:2
18:3
24:4
30:5
36:6
There would be approximately between 30-36 patients with only flu-like systems. Hope this helps! :)
Answer:
The estimated impact of the experiment of offering test preparation classes is:
= 8 scores (in performance improvement).
Step-by-step explanation:
Average standardized-test score for the first 10 high schools = 69
Average standardized-test score for the second 10 high schools = 70
After 6 months:
Average standardized-test score for the first 10 high schools offered test preparation classes = 78
The change in the average standardized-test score for the first 10 high schools = 9 (78 - 69)
Average standardized-test score for the second 10 high schools not offered test preparation classes = 71
The change in the average standardized-test score for the second 10 high schools not offered the prep = 1 (71 - 70)
The estimated impact of the experiment of offering test preparation classes is:
= 9 - 1
= 8.
Answer:
10
Step-by-step explanation:
8+5+15+12+10= 50 / 5 = 10
Since 10 cm is bigger than 1 mm, the scale drawing is bigger
Answer:
3 1/3
Step-by-step explanation:
<u>Step 1</u> is to look at the problem.
Here, you notice that the first two numbers have fractions that are quarters. The total of those two fractions is 1/4 + 3/4 = 4/4 = 1.
So, the sum of the first two numbers is ...
1 1/4 + 3/4 = 1 +(1/4 +3/4) = 1 +1 = 2
<u>Step 2</u> is to add the next mixed number, which has a fraction with a different denominator. Since you have no fractions to add at this point, the sum is just ...
2 + 1 1/3 = 3 1/3
_____
<em>Comment on adding fractions</em>
Generally, adding fractions requires you determine a common denominator. Often, you are asked to find the <em>least</em> common denominator, but that isn't necessary. Sometimes that can save the work of reducing the fraction that results, but sometimes it makes more work.
Here, a common denominator for fourths and thirds would be twelfths:
1/4 = 3/12
1/3 = 4/12
However, since adding the fourths results in an integer, no common denominator is necessary.
