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garri49 [273]
3 years ago
6

Can y'all please help me thanks u

Mathematics
2 answers:
Flura [38]3 years ago
8 0

Answer:

Step-by-step explanation:

15. A is the answer because you need to divide the top by the bottom

16.B

mihalych1998 [28]3 years ago
3 0
15. A is the answer because you need to divide the top by the bottom
16.B
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Solve For X. Solve similar triangles (advanced)​
satela [25.4K]
4+3 = 7
7^2 +6^2
49+36 = 85
Radical85 = 9.21
So x will be 3.9
3 0
3 years ago
In a company 85% of the workers are men if 510 women work for the company how many workers are there in all
tester [92]

Answer:

3400 workers

Step-by-step explanation:

85% of men that means 15% are women

15% = 510

15/100= 510/x

100x510=51000

51000/15 =3400

x=3400

3 0
3 years ago
Ples help and ples give derect awnser not a link you will get brainly if u do
slamgirl [31]
Im sorry i don’t know this but you should try photomath, it might help!
7 0
3 years ago
What is the value of n ?
tino4ka555 [31]

Answer:

the answer to this question is n=5

4 0
2 years ago
HELPPPP- you just got your driver's license. Your parents buy you a car and agree to let you pay them back over a period of 70 m
Nitella [24]

Using the monthly payments formula, it is found that a car with a value of at most $25,293.

<h3>What is the monthly payment formula?</h3>

It is given by:

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

In which:

  • P is the initial amount.
  • r is the interest rate.
  • n is the number of payments.

In this problem, we have that the parameters are given as follows:

A = 400, n = 70, r = 0.035.

Hence:

r/12 = 0.035/12 = 0.002917.

Then we have to solve for P to find the maximum value of the car.

A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}

400 = P\frac{0.002917(1.002917)^{70}}{(1.002917)^{70}-1}

P = \frac{400[(1.002917)^{70}-1]}{0.002917(1.002917)^{70}}

P = $25,293.

More can be learned about the monthly payments formula at brainly.com/question/26267630

#SPJ1

7 0
2 years ago
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