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tino4ka555 [31]
3 years ago
12

Please help me solve 4 inequalities and show work. Will get brainiest!!

Mathematics
1 answer:
FrozenT [24]3 years ago
5 0
1. y<span> ≤ 4x/3+5
2. y</span><span>< 6x/4+3</span>
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What number is 0.01 more than 23.1?<br><br> 23.11<br><br> 23.2<br><br> 24.1<br><br> 24.11
neonofarm [45]
23.11 cuz 23.1+0.01=23.11
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Help I only have till 11 I need HELP no links or you getting reported
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Help with what? there’s nothing?
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3x-8=10 Answer it correctly
shepuryov [24]

Answer:

x=6

Step-by-step explanation:

3x-8=10

+8      +8

3x=18

x=18/3

x=6

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4 years ago
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Find the area of the following shape. You must show all work to receive credit.
Svetach [21]

Answer:

8

Step-by-step explanation:

Split up the shape into three smaller shapes: a triangle at the top, a 1 by 2 rectangle, and a triangle at the bottom left. The 1 by 2 rectangle has an area of 2. The triangle at the top has an area of (4*2)/2 = 4, and the triangle at the bottom right has an area of (2*2)/2 = 2.

Therefore, the total area of the shape is 2 + 4 + 2 = 8

Hope this helped!

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8 0
2 years ago
Consider the function f(x) = the quantity x squared minus x minus 12 all over the quantity x plus 3. Describe the graph of this
FromTheMoon [43]

Answer:

The graph of f(x) is discontinuous at x= -3. The x and y-intercepts or he function f(x) are (4,0) and (0,-4) respectively. The graph of the function is a straight line.

Step-by-step explanation:

The given function is

f(x)=\frac{x^2-x-12}{x+3}

f(x)=\frac{x^2-4x+3x-12}{x+3}

f(x)=\frac{x(x-4)+3(x-4)}{x+3}

f(x)=\frac{(x-4)(x+3)}{x+3}

Cancel out the common factor (x+3).

f(x)=x-4

It is a linear equation and it will give a straight line.

Put x=0, to find the y-intercept.

f(x)=0-4

f(x)=-4

Therefore the y-intercept is (0,-4).

Put x=0, to find the x-intercept.

0=x-4

4=x

Therefore the x-intercept is (4,0).

At x= -3 the value of denominator is 0, therefore the function is undefined for x= -3.

As x approaches toward x=-3 from left and right, the value of function approaches towards y=-7.

The function is discontinuous at x= -3.

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