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3 years ago

11. A newborn grew from 11 inches to 16 inches in the first few weeks after birth. What is the

Mathematics

1 answer:

Ainat [17]3 years ago

5 0

Answer:

The newborn grew by forty-five percent.

Step-by-step explanation:

(16-11)/11 * 100

= 5 / 11 * 100

= 0.454545... * 100

≅45 %

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Solve for d in terms of r

Zarrin [17]

Hello!

Answer:

d=2r

Step-by-step explanation:

Simplify both sides and isolate the variable.

Hope this helps!

5 0

3 years ago

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How many solutions does the equation have? show your work.

Inessa05 [86]

All real numbers

7w-(2+w) = 2(3w-1)

Expand

7w-(2+w)= 6w-2

7w-2-w=6w-2

Group like terms

6w-2=6w-2

Add 2 to both sides

6w=6w

subtract 6w from both sides

0=0

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3 years ago

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What is the coefficient of the x^5y^5- term in the biomial expansion of (2x-3y)^10

jasenka [17]

<u>Answer:</u>

The coefficient of $x^{5} \times y^{5} \text { is }=\left(252 \times 2^{5} \times(-3)^{5}\right)=252 \times 32 \times 243=1959552$

<u>Solution: </u>

The given expression is $(2 x-3 y)^{10}$

As per binomial theorem, we know,

$(x+y)^{n}=\sum n C_{k} x^{n-k} y^{k}$

Now here a = 2x, b = (- 3y) and n = 10 and k = 0,1,2,….10

Now $x^{5}\times y^5$ will be the 6 term where k =5

Now, $\mathrm{T}_{6}=10 \mathrm{C}_{5} \times(2 \mathrm{x})^{(10-5)} \times(-3 \mathrm{y})^{5}=10 \mathrm{C}_{5} 2^{5} \times \mathrm{x}^{5} \times(-3)^{5} \times \mathrm{y}^{5}$

So, the coefficient of $x^{5} \times y^{5} \text { is }=10\left(5 \times 2^{5} \times(-3)^{5}\right$ .

$10 \mathrm{C}_{5}=\frac{10 !}{5 ! \times(10-5) !}=\frac{10 !}{5 !+5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6 \times 5 !}{5 ! \times 5 !}=\frac{10 \times 9 \times 8 \times 7 \times 6}{5 \times 4 \times 3 \times 2 \times 1}=\left(\frac{30240}{120}\right)=252$