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3 years ago

PLEASE HELP ASAP! I NEED TO PASS THIS TEST!

Mathematics

1 answer:

Nataly [62]3 years ago

4 0

X^2+20x+10 that's the answer

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Solve the equation log^7b>2

ahrayia [7]

Answer:

b > 12.71

Step-by-step explanation:

Here in this question we have to solve the inequality equation given for b (An unknown variable}

Now, the equation is $(\log b)^{7} > 2$

⇒ $\log b > 2^{\frac{1}{7} }$

We are taking the base of the log here is 10.

So, $10^{(\log b)} > 10^{2^{\frac{1}{7} } }$ {Since $10^{\log x} =x$ and $e^{\ln x} = x$ }

⇒ b > 12.71 (Approximate) (Answer)

3 0

3 years ago

Please Help

artcher [175]

Multiply equation B by 2.
Multiply equation A by 2
Multiply equation B by 3.
Multiply equation A by -3

Answer: D

5 0

3 years ago

Find the center and radius of this circle x^2+y^2-6x-10y+30=0

Artist 52 [7]

Answer:

Center: (3,5)

Radius: 2

Step-by-step explanation:

x² + y² - 6x - 10y + 30 = 0

Put equation into center-radius form. First regroup terms:

(x²-6x) + (y²-10y) = -30

Complete the squares:

(x²-6x+3²) + (y²-10y+5²) = -30 + 3² + 5²

(x-3)² + (y-5)² = 4 = 2²

Center: (3,5)

Radius: 2

8 0

2 years ago

How to solve y=350(1+0.75)t

maria [59]

350(1+0.75)t (add the numbers)
350*1.75t (Calculate the product)
612.5 t

6 0

2 years ago

Read 2 more answers

A ladder 16 feet long is leaning against the wall of a tall building. The base of the ladder is moving away from the wall at a r

svet-max [94.6K]

Answer:

a. 0.588

b. 0.0722

c. 4.576 sqft/sec

Step-by-step explanation:

Let b and h denote the base and height as indicated in the diagram. By pythagoras theorem, $h^2 + b^2 = 16^2 = 256 \dotsc\;(1)$ because it is a right angle triangle.

It is given that $\frac{db}{dt} = 1$

Now differentiate (1) with respect to t (time) :

$\displaystyle{2h\frac{dh}{dt} + 2b\frac{db}{dt} = 0 \implies \frac{dh}{dt} = -\frac{b}{h} \frac{db}{dt}}$

$\displaystyle{=-\frac{b}{\sqrt{256 - b^2}} \frac{db}{dt} = -\frac{8}{13.856} \times 1 = -0.588}$

The minus sign indicates that the value of h is actually decreasing. The required answer is 0.588.

b. From the diagram, infer that $16 \sin{\theta} = b$ . When b = 8, then $\theta = \arcsin{0.5} = \ang{30}$ .

Differentiate the above equation w.r.t t

$\displaystyle{16 \cos{\theta} \frac{d\theta}{dt} = \frac{db}{dt} \implies \frac{d\theta}{dt} = \frac{1}{16 \cos{\theta}} = \frac{1}{13.856} = \mathbf{0.0722}}$

c. The area of the triangle is given by $A = 0.5\times h \times b$ . Differentiating w.r.t t,

$\displatstyle{\frac{dA}{dt} = 0.5 b \frac{dh}{dt} + 0.5 h \frac{db}{dt}}$

Plugging in b = 8, h = 13.856, $\frac{dh}{dt} = -0.588$ ,

$\frac{dA}{dt} = -2.352 + 6.928 = \mathbf{4.576 ft^2/sec}$

8 0

3 years ago