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stich3 [128]
1 year ago
11

Determine which equation is parallel and perpendicular to jk​

Mathematics
1 answer:
3241004551 [841]1 year ago
4 0

None of the equations are parallel or perpendicular to the line jk.

<h3>How to know equations that are parallel and perpendicular?</h3>

The equation of a line can be interpreted as follows:

y = mx + b

where

  • m = slope
  • b = y-intercept

Therefore,

Parallel lines have the same slope(m).

Perpendicular line follows the principle below:

  • m₁ m₂ = -1

Therefore, let's find equation of jk

(-5, 5)(1, -5)

m = -5 - 5 / 1 + 5 = -10 / 6 = - 5 / 3

using (1, -5)

-5 = - 5 / 3 (1) + b

b = -5 + 5 / 3 = -15 + 5 / 3 = -10 / 3

Therefore,

y = -5 / 3 x - 10 / 3

m = - 5 / 3

6x + 10y = 11

10y = -6x + 11

y = - 6 / 10 x + 11 / 10

y = - 3 / 5 x + 11 / 10

hence, m = - 3 / 5

5x - 3y = 8

3y = 5x - 8

y = 5 / 3 x - 8/3

m = 5 / 3

The equation

learn more equation here: brainly.com/question/14379343

#SPJ1

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Step-by-step explanation: In this problem, we're asked to state the domain and range for the following relation.

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Read 2 more answers
Please answer the following question. Also please answer if you actually know it.
Iteru [2.4K]

Given : f(x)= 3|x-2| -5

f(x) is translated 3 units down and 4 units to the left

If any function is translated down then we subtract the units at the end

If any function is translated left then we add the units with x inside the absolute sign

f(x)= 3|x-2| -5

f(x) is translated 3 units down

subtract 3 at the end, so f(x) becomes

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f(x) is translated   4 units to the left

Add 4 with x inside the absolute sign, f(x) becomes

f(x)= 3|x-2 + 4| -5 -3

We simplify it and replace f(x) by g(x)

g(x) = 3|x + 2| - 8

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