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valina [46]
3 years ago
15

Given that A'B'C' is the image of ABC under a reflection, enter that equation of the line of reflection.

Mathematics
1 answer:
PolarNik [594]3 years ago
7 0

Answer:

sooooo

Step-by-step explanation:

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Can anyone solve this?
Serhud [2]

Answer:

A) 96 cm

Step-by-step explanation:

Split into three parallelograms

Shape 1: 6 by 7     6×7=42

Shape 2: 3 by 4    3×4=12

Shape 3: 6 by 7    6×7=42

42+12+42=96

6 0
3 years ago
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So I need help with 1 over x minus 8 so like 1/x-8 this is a negative exponent
Trava [24]

Answer and Step-by-step explanation:

one divided by (in parentheses) x minus eight should look like this:

\frac{1}{x-8}

This is a graph of this expression.

#teamtrees #WAP (Water And Plant)

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3 years ago
What is the equation of a circle with center (5, -8) and diameter 4?
klio [65]

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is 8 porque s mi nose maje

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4 years ago
A submarine dives below the surface, heading downward in nine moves. If each move downward was 180
Maslowich
The submarine would be 1,620 ft if i’m understanding the question correctly
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3 years ago
A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
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