All categories

3 years ago

Given that A'B'C' is the image of ABC under a reflection, enter that equation of the line of reflection.

Mathematics

1 answer:

PolarNik [594]3 years ago

7 0

Answer:

sooooo

Step-by-step explanation:

You might be interested in

What shape do degree 3 functions have?

weqwewe [10]

Answer: Third degree polynomials are also known as cubic polynomials. Cubics have these characteristics: One to three roots. Two or zero extrema.

HOPE THIS HELPS

Please brainliest

5 0

3 years ago

Read 2 more answers

F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)

Butoxors [25]

Answer:

The function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

Explanation:

Given the functions;

$\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}$

Solving for the function;

$(g\circ f)(x)=g(f(x))$

so, we have;

$\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}$

Therefore, the function (gof)(x) is;

$(g\circ f)(x)=8x^2+36x+49$

5 0

1 year ago

An orchard owner wants to plant 64 cherry tree seedlings and 96 peach tree seedlings in rows. Each row is to have the same numbe

-BARSIC- [3]

Answer:

Given:

cherry tree seedlings : 64

peach tree seedlings : 96

64/96 : Simplify this fraction

64 / 8 = 8 / 4 = 2

96 / 8 = 12 / 4 = 3

2 and 3 number of seedlings per row

64 / 2 = 32

96 / 3 = 32

number of rows

The maximum number of rows that the owner can plant is 32 rows with 2 cherry tree seedlings and 3 peach tree seedlings.

5 0

3 years ago

Read 2 more answers

Complete parts (a) through (c) below.

Yuki888 [10]

Answer:

a) $t_{crit}= 1.34$

b) $t_{crit}=-2.539$

c) $t_{crit}=\pm 2.228$

Step-by-step explanation:

Part a

The significance level given is $\alpha=0.1$ and the degrees of freedom are given by:

$df = n-1= 15$

Since we are conducting a right tailed test we need to find a critical value on the t distirbution who accumulates 0.1 of the area in the right and we got:

$t_{crit}= 1.34$

Part b

The significance level given is $\alpha=0.01$ and the degrees of freedom are given by:

$df = n-1= 20-1=19$

Since we are conducting a left tailed test we need to find a critical value on the t distirbution who accumulates 0.01 of the area in the left and we got:

$t_{crit}=-2.539$

Part c

The significance level given is $\alpha=0.05$ and $\alpha/2 =0.025$ and the degrees of freedom are given by:

$df = n-1= 11-1=10$

Since we are conducting a two tailed test we need to find a critical value on the t distirbution who accumulates 0.025 of the area on each tail and we got:

$t_{crit}=\pm 2.228$

4 0

3 years ago

Which table contains points that lie on a line with a slope of −2?

o-na [289]

C, or the top right table. I don’t exactly feel like explaining unless you really want me to... in that case lmk.

7 0

3 years ago

Read 2 more answers

Given that A'B'C' is the image of ABC under a reflection, enter that equation of the line of reflection.￼

Given that A'B'C' is the image of ABC under a reflection, enter that equation of the line of reflection.