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balandron [24]
2 years ago
8

Should a quadrilateral have at least one pair of parallel sides?

Mathematics
1 answer:
Taya2010 [7]2 years ago
6 0

Answer:

it have two parallel sides

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Simplify the equation. (5xE2 - 3x) - (5xE2 - 3x+1)
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Answer:

\huge \boxed{\mathrm{-1}}

Step-by-step explanation:

(5xe^2  - 3x) - (5xe^2  - 3x+1)

Distribute negative sign.

5xe^2  - 3x- 5xe^2  +3x-1

Combine like terms.

0xe^2 +0x-1

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3 years ago
Match the reasons with the statements.
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Answer:

Concept: Mathematical Derivation

  1. We are given x^2 +6x+2x+12
  2. Hence we simplify: x^2 + 8x +12
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Solve for B - PLEASE HELP IMMA DIE
Marta_Voda [28]
First, you would have to add d to both sides to get rid of it
x+d=ab+c/b
Then you would multiply b by both sides to get rid of the b in the denominator
x+d(b)=ab+c
After that, you would subtract c from both sides
x+d(b)-c=ab
Then you would divide both sides by a
x+d(b)-c=b
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6 0
2 years ago
PLZZZ HELP ME OUT THIS DUE RIGHT NOW AND I FREAKING OUT PLEASE HELP ME P.S YOU HAVE WRITE ANSWERS FOR ALL OF THEM
Nimfa-mama [501]

<em>Answer:</em>

<em>a is greater than 1, so a−1 is positive.</em>

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<em>The distance between a and 1 appears to be less than the distance between 1 and 0, so it looks like a is less than 2. Thus a−2 is negative.</em>

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<em>b is negative, so −b is positive.</em>

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<em>The distance between a and 0 appears to be less than the distance between b and 0, so it looks like |a| is less than |b|. Since b is negative and a is positive, a+b is negative.</em>

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<em>a−b = a+−b. Since b is negative, −b is positive. a is also positive. Thus, a−b is positive.</em>

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<em>Since |a| and |b| are both greater than 1, |ab| is also greater than 1 (this builds on the intuition students gained in fifth grade as in 5.NF.5). ab is negative since a is positive and b is negative. Thus, ab+1 is negative.</em>

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