Answer:
y=1/2(x-1)
Step-by-step explanation:
If x=t^2 and t>0, then t=sqrt(x).
If t=sqrt(x) or x^(1/2) and y =1-1/t, then y=1-x^(-1/2).
The x-intercept is when y=0.
So we need to solve 0=1-x^(-1/2) to find point P.
Add x^(-1/2) on both sides: x^(-1/2)=1.
Raise both sides to -2 power: x=1
So point P is (1,0).
Let's find tangent line at point (1,0).
We will need the slope so let's differentiate.
y'=0+1/2x^(-3/2)
y'=1/(2x^(3/2))
The slope at x=1 is y'=1/(2[1]^(3/2))=1/(2×1)=1/2.
Recall point-slope form is y-y1=m(x-x1).
So our line we are looking for is y-0=1/2(x-1)
Let's simplify left hand side y=1/2(x-1)
Answer:
4 pairs of pants
Step-by-step explanation:
divide 94.24 by 23.56 and you will get 4 :)
Multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
<h3>How to expand quadratic equations?</h3>
We want to expand the quadratic equation given as;
(x + 2)(4x - 3)
Multiplying out gives us;
4x² + 8x - 3x - 6
⇒ 4x² + 5x - 6
Thus, we can conclude that multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
Read more about Quadratic equations at; brainly.com/question/1214333
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<span>The total number (n) = 28. This includes the number of cats (c) and the number of dogs (d), which is three times the number of cats. Therefore n = c + d and 28 = c + 3c. 28 = 4c. C = 28/4. C = 7. Kim trained 7 cats.</span>
