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Yuri [45]
2 years ago
5

There was a Rockets game on Friday and Saturday.

Mathematics
2 answers:
Bingel [31]2 years ago
7 0
32982 people

18055-3128=14927
18055+14927=32982
katrin [286]2 years ago
6 0
18,055
-
3,138
———-
14,927

14,927
+
18,055
———-
32,982
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The cost of one pound of bananas is greater than $0.41 and less than $0.50. Sarah pays $3.40 for x pounds of bananas. Which ineq
vredina [299]

Answer:

0.41<3.40/x<0.50

Step-by-step explanation:

Given that the cost of one pound of bananas is greater than $0.41 and less than $0.50. That is,

If the cost of one banana is P, then, the inequality will be

0.41 < P < 0.50

Sarah pays $3.40 for x pounds of bananas. The inequality that represents the range of possible pounds purchased will be achieved by below

3.40/0.41 = 8.29

3.40/0.50 = 6.8

Therefore, the inequality that represents the range of possible pounds purchased is

6 < x < 9 this is the same as 0.41<3.40/x<0.50

6 0
3 years ago
You buy a game for $40, and the sales tax is $2. What percent of the game price are you paying in sales tax?
Andreas93 [3]
To get the answer we can use proportion
40$ ------------- 100%
2$ ---------------- x
crossmultiply now
40x=2*100           /:40
x=200:40
x=5% - its the answer
6 0
3 years ago
Read 2 more answers
Find the quotient of the quantity negative 5 times x to the 3rd power plus 20 times x to the 2nd power minus 25 times x all over
Alona [7]
Negative x squared minus 4 x plus 5
8 0
3 years ago
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How your day been? Mines been kinda great.​
garri49 [273]

Answer:

kinda bad

Step-by-step explanation:

but overall good

6 0
3 years ago
Taisha uses the elliptical cross- trainer at the gym. Her general goal is to burn 280 calories per workout, but she varies by as
Fed [463]

Given - Taisha has a general goal is to burn the 280 calories.

she is varies by the 25 calories.

Find out the maximum and minimum of calories burn by the taisha.

To proof -

let us assume that the calories burn by the taisha be x.

as given the calories are varies by the 25 calories.

then the maximum calories equation becomes

x-25 = 280

x = 280 + 25

x = 305

the maximum calories burn by the taisha is 305 calories.

minimum calories equationbecomes

x + 25 = 280

x = 255

The minmum calories burn by the taisha is 255 calories.

Hence proved






8 0
3 years ago
Read 2 more answers
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