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Zanzabum
3 years ago
11

At the beginning of summer, Mark has $200 in savings and Ryan has $350 in savings the brothers have mowing jobs set up for the s

ummer. Because mark is older, he receives $15 for each mowing job. The others parents pay for the fuel used to mow, so all the money the brothers earn goes to savings

Mathematics
1 answer:
Vanyuwa [196]3 years ago
4 0

9514 1404 393

Answer:

  • Mark: s = 200 +20j
  • Ryan: s = 350 +15j
  • 30 jobs

Step-by-step explanation:

The amount in savings (s) will be the initial amount plus the product of the pay per job and the number of jobs (j).

<u>Mark</u>

He initially has $200, and is paid $20 per job. His savings will be ...

  s = 200 +20j

<u>Ryan</u>

He initially has $350, and is paid $15 per job. His savings will be ...

  s = 350 +15j

<u>Same Savings</u>

The savings will be the same when the difference between the amounts is zero:

  s - s = 0

  (200 +20j) -(350 +15j) = 0 . . . . . substitute the expressions for s

  -150 +5j = 0 . . . . . collect terms

  -30 +j = 0 . . . . . . . divide by 5

  j = 30 . . . . . . add 30

The brothers will have the same amount in savings after they each work 30 jobs.

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hoa [83]
Factors of 84: 1, 2<span>, </span>3<span>, 4, 6, </span>7<span>, 12, </span>14<span>, </span>21<span>, </span>28<span>, </span>42<span>, 84. Prime factorization: 84 = </span>2<span> x </span>2<span> x </span>3<span>x </span>7<span> which can also be written (</span>2^2<span>) x </span>3<span> x </span>7<span>.</span>
6 0
4 years ago
Read 2 more answers
Jenny used 15 centimeters of tape to wrap 5 presents. How much tape will Jenny need in all if she has to wrap 10 presents? Assum
Scorpion4ik [409]

Answer:

30

Step-by-step explanation:

15cm for 5

5 x 2=10

15 x 2 = 30

7 0
3 years ago
|x| + 4 &gt; 7 plz help and hurry
Talja [164]

Answer:

The solution is (-\infty,-3)\cup(3,\infty).

Step-by-step explanation:

Given:

The inequality given is:

|x|+4>7

In order to simplify for 'x', we first isolate 'x' on one side.

Adding -4 on both sides, we get:

|x|+4-4>7-4\\\\|x|>3

Now, |x| is an absolute value function which is defined as:

|x|=\left \{ {{-x}\ \ x

Therefore, the given inequality can be rewritten as:

-x > 3\\x and x > 3

Therefore, the solution is (-\infty,-3)\cup(3,\infty).

4 0
3 years ago
Given an arithmetic sequence with a3=5 and a5=19, find the 24th term.
krok68 [10]

The 24th term is 152

Step-by-step explanation:

The formula of the nth term of an arithmetic sequence is:

a_n=a+(n-1)d , where

  • a is the first term
  • d is the common difference between consecutive terms

The third term means n = 3

∵ a_3=a+(3-1)d

∴ a_3=a+2d

∵ a_3 = 5

- Equate the right hand sides of the third term

∴ a + 2d = 5 ⇒ (1)

The fifth term means n = 5

∵ a_5=a+(5-1)d

∴ a_5=a+4d

∵ a_5 = 19

- Equate the right hand sides of the fifth term

∴ a + 4d = 19 ⇒ (2)

Now we have a system of equations to solve it

Subtract equation (1) from equation (2) to eliminate a

∴ 2d = 14

- Divide both sides by 2

∴ d = 7

- Substitute the value of d in equation (1) to find a

∵ a + 2(7) = 5

∴ a + 14 = 5

- Subtract 14 from both sides

∴ a = -9

The twenty fourth term means n = 24

∵ a = -9 and d = 7

- Substitute the values of a and d in the formula of the nth term

∴ a_24=-9+(24-1)(7)

∴ a_24=-9+(23)(7)

∴ a_24=-9+161

∴ a_24=152

The 24th term is 152

Learn more:

You can learn more about the arithmetic sequence in brainly.com/question/7221312

#LearnwithBrainly

5 0
3 years ago
The two dot plots show the number of miles ran by 14 students at the beginning and at the end of the school year compare each me
Naddika [18.5K]

The two dot plots are missing, so i have attached it.

Answer:

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

Step-by-step explanation:

From the attached image, we are told to compare the means for each plot to the nearest tenth.

Mean = Σx/n

Now, from the image, total number of miles run by the 14 students at the beginning of the school year is;

(1 × 7) + (2 × 8) + (4 × 9) + (4 × 10) + (2 × 11) + (1 × 12) = 133

Mean of miles run at the beginning of the school year = 133/14 = 9.5 miles

Again, from the table, total miles run at the end of the school year = (2 × 8) + (2 × 9) + (4 × 10) + (3 × 11) + (3 × 12) = 143

Mean of miles run at the end of the school year = 143/14 = 10.2 miles

Thus;

The mean at the beginning of the school year was 9.5 miles and the mean at the end of the school year was 10.2 miles

5 0
3 years ago
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