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Sergio039 [100]
3 years ago
15

Giving braileist for answer

Mathematics
2 answers:
sergij07 [2.7K]3 years ago
6 0

Answer:

The answer is A

because they are multiplying

Margaret [11]3 years ago
4 0

Answer:

a is the answer

Step-by-step explanation:

a is the answer because the way they are being multiplied are consistent, while the others arent.

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PLEASE HELP!!!!!
Masja [62]

Given:

Center of hyperbola is at (h,k).

To find:

The standard forms of a hyperbola.

Solution:

We know that, standard forms of a hyperbola are

1. For Horizontal hyperbola:

\dfrac{(x-h)^2}{a^2}-\dfrac{(y-k)^2}{b^2}=1

2. For Vertical hyperbola:

\dfrac{(y-k)^2}{a^2}-\dfrac{(x-h)^2}{b^2}=1

where, (h,k) is center of the hyperbola.

Therefore, the correct option is B.

4 0
3 years ago
It took Joe 3 hours swimming at a speed of 12 miles per hour to swim along the Charles River. If Jennifer is swimming the same p
polet [3.4K]

Answer:

4 hours

Step-by-step explanation:

3 x 12 = 36

36/9 = 4

7 0
3 years ago
Find two consecutive odd integers such that the sum of the first and three times the second is 98
Mrac [35]

Answer:

23 and 25

Step-by-step explanation:

x and x+2

x+3(x+2)=98

x+3x+6=98

4x=92

x=23

x+2=25

3 0
3 years ago
I don’t know how to do it
Marina86 [1]

Answer:

option D

Step-by-step explanation:

3 0
3 years ago
Two different suppliers, A and B, provide a manufacturer with the same part. All supplies of this part are kept in a large bin.
koban [17]

Answer:

The probability of selecting a non-defective part provided by supplier A is 0.807.

Step-by-step explanation:

Let <em>A</em> = a part is supplied by supplier A, <em>B</em> = a part is supplied by supplier B and <em>D</em> = a part is defective.

<u>Given</u>:

P (D|A) = 0.05, P(D|B) = 0.09

A supplies four times as many parts as B, i.e. n (A) = 4 and n (B) = 1.

Then the probability of event <em>A</em> and <em>B</em> is:

P(A)=\frac{n(A)}{n(A)+N(B)}= \frac{4}{4+1}=0.80\\P(B)\frac{n(B)}{n(A)+N(B)}= \frac{1}{4+1}=0.20

Compute the probability of selecting a defective product:

P(D)=P(D|A)P(A)+P(D|B)P(B)\\=(0.05\times0.80)+(0.09\times0.20)\\=0.058

The probability of selecting a non-defective part provided by supplier A is:

P(A|D')=\frac{P(D'|A)P(A)}{P(D')} = \frac{(1-P(D|A))P(A)}{1-P(D)}\\=\frac{(1-0.05)\times0.80}{(1-0.058)}\\ =0.80679\\\approx0.807

Thus, the probability of selecting a non-defective part provided by supplier A is 0.807.

5 0
3 years ago
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