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shusha [124]
3 years ago
15

Who is in bishop cotton school shimla people there will get brainliest​

Mathematics
1 answer:
Marianna [84]3 years ago
8 0
The desired number of children per family in the United States is now about two. Despite the availability of a number of contraceptive options, close to 50% of pregnancies in the United States are unplanned, and approximately 25% of babies born are unwanted at the time of birth.
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Sarah has more than eight goldfish in her tank what inequality sign do you use to show this
shtirl [24]
X>8
Sarah has more than eight goldfish in her tank
4 0
3 years ago
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Mrs. Anderson is giving a test
Radda [10]

Answer:

Step-by-step explanation:

ok

7 0
4 years ago
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Find the sum of the first 50 terms.<br> -6,-2,2,6
Veseljchak [2.6K]

Answer:

4600

Step-by-step explanation:

There is a common difference d between consecutive terms, that is

d = - 2 - (- 6) = 2 - (- 2) = 6 - 2 = 4

This indicates the sequence is arithmetic with sum to n terms

S_{n} = \frac{n}{2} [ 2a₁ + (n - 1)d ]

where a₁ is the first term and d the common difference

Here a₁ = - 6 and d = 4 , then

S_{50} = \frac{50}{2} [ (2 × - 6) + (49 × 4) ]

     = 25(- 12 + 196)

     = 25 × 184

     = 4600

4 0
3 years ago
The distribution of the number of blocks a young child can stack before their tower falls is approximately Normally distributed
krok68 [10]

Add them together and then divide by the number of numbers

like this:

joe had 7 beans

eric had 5

julie had 2

add them

you get 14

now divide by 3

4.6 with a bunch of 6

8 0
3 years ago
Read 2 more answers
The mean of the sample is 24.444 squares with a standard deviation of 2.45 squares. Single-ply toilet paper requires 26 squares
Romashka [77]

Answer:

t = -2.69 , p = 0.0078

Step-by-step explanation:

We have the following data:

Sample Mean = x = 24.444

Sample Standard Deviation = s = 2.45

Sample size = n = 18

Josh wants to test that mean number is lesser than 26. So our test value is 26 i.e.

u = 26

Since Josh wants to test that mean would be fewer than 26, so this would be a left tailed test with a less than sign in Alternate Hypothesis. Therefore, the hypothesis would be:

H_{o}: u\geq 26\\H_{a}: u

Since, we do not know the value of Population standard deviation, and we have the value of sample standard deviation, we will use One-Sample t-test for the population mean.

The formula to calculate the test-statistic would be:

t=\frac{x-u}{\frac{s}{\sqrt{n}}}

Substituting the values in this formula gives us:

t=\frac{24.444-26}{\frac{2.45}{\sqrt{18}}}\\t=-2.69

This means, the test statistic would be -2.69

Since, the sample size is 18, the degrees of freedom would be:

Degrees of freedom = df = n - 1 = 17

To find the p-value we need to check the p-value against test statistic of 2.69, with 17 degrees of freedom and One-tailed test. This value comes out to be:

p-value = 0.0078

Therefore, the correct answer would be:

t = -2.69 , p = 0.0078

4 0
3 years ago
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