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3 years ago

Can someone help me find x

Mathematics

1 answer:

Natasha2012 [34]3 years ago

6 0

Answer:

30°

Step-by-step explanation:

4x-12 = 108

4x = 120

x=30

4(30)-12 = 108 (Just to check)

120-12 =108

108=108

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PLZ HELP ME I NEED THIS FAST WILL GIVE BRAINLIEST

Bas_tet [7]

Step-by-step explanation:

The formula the amusement parc use is 100y-39000=55(x-800)

The slope intercept form of a function is wriiten generally as:

y = mx+c

m is a slope
c is a constant and represents the y-intercept
x is a variable
y is the input of the function

Let's rewrite our equation in the precedent form

100y-39000 = 55(x-800)
100y -39000 = 55x-44000 add 39000 in both sides
100y-39000+39000 = 55x-44000+39000
100y = 55x-5000 divide both sides by 100
y = 0.55x-50

The slope intercept form of this equation is:

y= 0.55x-50

4 0

3 years ago

Read 2 more answers

Write an expression for 213 increased by d.

Tcecarenko [31]

Write an expression for 213 increased by d: $213+d=x$

6 0

3 years ago

What is the inverse of the function f(x) = 2x – 10?

Lana71 [14]

Answer:

$h(x)=\dfrac{x}{2}+5$

Step-by-step explanation:

You are given the function $f(x)=2x-10$ . To find the inverse function $f^{-1}(x)$ do such steps:

1. Rewrite the function f(x) as

$y=2x-10$

2. Express x in terms of y:

$y+10=2x\\ \\x=\dfrac{y}{2}+5$

3. Change x into y and y into x:

$y=\dfrac{x}{2}+5$

Now, the inverse function is

$f^{-1}(x)=\dfrac{x}{2}+5$

7 0

3 years ago

Read 2 more answers

Find the 31st term of the following sequence.<br><br> 9, 15, 21, ...

Marrrta [24]

The 31st term of this sequence is 189.
9, 15, 21, 27, 33 (5), 39, 45, 51, 57, 63 (10), 69, 75, 81, 87, 93 (15), 99, 105, 111, 117, 123 (20), 129, 135, 141, 147, 153 (25), 159, 165, 171, 177, 183 (30), 189.

8 0

3 years ago

The width of a rectangle is increasing at a rate of 2 cm/sec, while the length increases at 3 cm/sec. At what rate is the area i

lorasvet [3.4K]

Answer:

The area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

Step-by-step explanation:

Given : The width of a rectangle is increasing at a rate of 2 cm/ sec. While the length increases at 3 cm/sec.

To find : At what rate is the area increasing when w = 4 cm and I = 5 cm?

Solution :

The area of the rectangle with length 'l' and width 'w' is given by $A=l w$

Derivative w.r.t 't',

$\frac{dA}{dt}=w\frac{dl}{dt}+l\frac{dw}{dt}$

Now, we have given

$\frac{dl}{dt}=3\ cm/s$

$l=5\ cm$

$\frac{dw}{dt}=2\ cm/s$

$w=4\ cm$

Substitute all the values,

$\frac{dA}{dt}=(4)(3)+(5)(2)$

$\frac{dA}{dt}=12+10$

$\frac{dA}{dt}=22\ cm^2/s$

Therefore, the area of the rectangle is increasing at a rate of $22\ cm^2/s$ .

4 0

3 years ago