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Morgarella [4.7K]
2 years ago
13

Find the sum. io + 10 5

Mathematics
1 answer:
cestrela7 [59]2 years ago
6 0

Answer:

The answer is -0.6

Step-by-step explanation:

I hope this helps. Sorry if I am wrong.

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What is 12÷1935.6 ? i’m so confused and I need help with the steps
Naddik [55]

Answer:

161.3000

Step-by-step explanation:

4 0
1 year ago
Can someone help pls​
scZoUnD [109]

Answer:

8) 10 m 9) 26 in 10) 51 m 11) 50 ft 12) 19.4 cm 13) 177.9 m 14) 40 15) 12 16) 14.7 17) 12.1

Step-by-step explanation:

You may solve the problems by using the Pythagorean Theorem which states that c^2 = a^2 + b^2, or in other words, the hypotenuse squared is equal to the sum of the legs squared.

Hope this helps! :-)

3 0
2 years ago
At a table Tennis tournament, two games went on for a total of 32 minutes long. One game took 12 minutes longer than the other.
Kaylis [27]
The answer is 44 minutes
5 0
3 years ago
A store is having a 20% off sale on all merchandise If Mai buys one item and save $13 what was the original price of her purchas
katrin [286]

Answer:

Step-by-step explanation:

20% off...and she saves $13

so 20% of what number is 13

0.20x = 13

x = 13/0.20

x = 65 <== original price

7 0
2 years ago
Read 2 more answers
What is the justification for the first step in proving the formula for factoring the sum of cubes?
Anna11 [10]

Explanation:

The formula isnt correctly written, it should state:

a^3+b^3 = (a+b)(a^2-ab+b^2)

You have to start from (a+b)(a^2-ab+b^2)  and end in a³+b³. On your first step, you need to use the distributive property.

(a+b)(a^2-ab+b^2) = a*(a^2-ab+b^2) + b*(a^2-ab+b^2)

This is equal to

a*a^2-a*(ab) + a*b^2 + b*a^2-b*(ab) + b*b^2 = a^3 - a^2b + ab^2 +ba^2 -b^2a +b^3

Note that the second term, -a²b, is cancelled by the fourth term, ba², and the third term, ab², is cancelled by the fifht term, -b²a. Therefore, the final result is a³+b³, as we wanted to.

5 0
3 years ago
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