Answer:
Periodic table, in full periodic table of the elements, in chemistry, the organized array of all the chemical elements in order of increasing atomic number—i.e., the total number of protons in the atomic nucleus. ... Mendeleyev in the mid-19th century, has been of inestimable value in the development of chemistry.
Explanation:
Answer:
Third Law of motion. (answer C)
Explanation:
This is an example of Newton's Third Law of motion which normally translates into Action/Reaction. That is : the expelled air exerts a force in the direction opposite to that of the motion of the air that goes out. It is the same as propulsion in a rocket.
1. Ur graph should have 2 vertical lines || , of equal height at mass 13 and 15.
2. One, because you have the mass, which in this case is 13 and the other 15, which has the same height. So it must be the isotope. By definition, an isotope has the same number of protons, but different number of neutrons.
3. to solve for fractional abundance, Let x = fraction of element: "I"-13
then fraction of "I"-15 must be 1-x
so you have: 13x + (15<span>)(1-x) = 13
solve for x.</span>
A. 6.59kj is the answer.
There you go!
Answer: The half-life of the compound is 93 minutes
Explanation:
Expression for rate law for first order kinetics is given by:
![t=\frac{2.303}{k}\log\frac{a}{a-x}](https://tex.z-dn.net/?f=t%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7Ba%7D%7Ba-x%7D)
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant =100
a - x = amount left after decay process = (100-36) = 64
a) for completion of 36 % of reaction
![60=\frac{2.303}{k}\log\frac{100}{100-36}](https://tex.z-dn.net/?f=60%3D%5Cfrac%7B2.303%7D%7Bk%7D%5Clog%5Cfrac%7B100%7D%7B100-36%7D)
![k=\frac{2.303}{60}\log\frac{100}{64}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7B60%7D%5Clog%5Cfrac%7B100%7D%7B64%7D)
![k=0.0074min^{-1}](https://tex.z-dn.net/?f=k%3D0.0074min%5E%7B-1%7D)
b) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
![t_{\frac{1}{2}}=\frac{0.693}{k}](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cfrac%7B0.693%7D%7Bk%7D)
![t_{\frac{1}{2}}=\frac{0.693}{0.0074min^{-1}}=93min](https://tex.z-dn.net/?f=t_%7B%5Cfrac%7B1%7D%7B2%7D%7D%3D%5Cfrac%7B0.693%7D%7B0.0074min%5E%7B-1%7D%7D%3D93min)
The half-life of the compound is 93 minutes