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3 years ago

Calculate the mass of magnesium oxide formed when 3.0 grams of magnesium reacts with excess oxygen.

Chemistry

1 answer:

BlackZzzverrR [31]3 years ago

3 0

Mg+O2=MgO
24 g. = 40 g
3 g. = x
$x = \frac{3 \times 40}{24} \\ x = 5 \: g$

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Maximum gravitational Force: $F_{gmax} = 1,026*10^{-08} N$

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Usually potassium hydrogen phthalate is kept very pure. But Stu Dent thinks the bottle of potassium hydrogen phthalate has been

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Answer:

1.784 g

Explanation:

The equation of the reaction is;

NaOH(aq) + KHC8H4O4(aq) --------> KNaC8H4O4(aq) + H2O(l)

Number of moles of NaOH reacted = 17.47/1000 * 0.5000 M

Number of moles of NaOH reacted =8.735 * 10^-3 moles

From the reaction equation;

1 mole of NaOH reacted with 1 mole of KHC8H4O4

Hence, 8.735 * 10^-3 moles of NaOH reacts with 8.735 * 10^-3 moles of KHP.

So,

Mass of KHP reacted = 8.735 * 10^-3 moles * 204.2 g/mol = 1.784 g

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