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Sonbull [250]
3 years ago
9

Calculate the mass of magnesium oxide formed when 3.0 grams of magnesium reacts with excess oxygen.

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
3 0
Mg+O2=MgO
24 g. = 40 g
3 g. = x
x =  \frac{3 \times 40}{24}  \\ x = 5 \: g
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<h3>Explanation</h3>

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500 milliliter of a 0.50 mol per liter "M" solution contains 0.25 moles of the solute. There are thus 0.25 moles of hydrogen ions and hydroxide ions in the two 0.500 milliliter solutions, respectively. They would combine to release 0.25 \times 56.2 \times 10^{3} = 1.405 \times 10^{4} \; \text{J} of energy.

Both the solution and the calorimeter absorb energy released in this neutralization reaction. Their temperature change is dependent on the heat capacity <em>C</em> of the two objects, combined.

The question has given the heat capacity of the calorimeter directly.

The heat capacity (the one without mass in the unit) of water is to be calculated from its mass and <em>specific</em> heat.

The calorimeter contains 1.00 liters or 1.00 \times 10^{3} \; \text{ml} of the 1.0 gram per milliliter solution. Accordingly, it would have a mass of 1.00 \times 10^{3} \; \text{g}.

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