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katovenus [111]
3 years ago
15

Help if possible, thanks.

Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

1,2,3,6 are congruent

Step-by-step explanation:

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Which set of ordered pairs is a function?
DochEvi [55]
A function is a set of ordered pairs in which no two different ordered pairs have the same x -coordinate. An equation that produces such a set of ordered pairs defines a function. What is the catch? There can be at most one output for every input.
4 0
3 years ago
Suppose that each of 935 smokers received a nicotine patch, which delivers nicotine to the bloodstream but at a much slower rate
nika2105 [10]

Answer:

26.2% of smokers,when given this treatment, would refrain from smoking for at least 6 months.

Step-by-step explanation:

In this problem, we have that:

935 smokers received the treatment(nicotine patch).

After 6 months, 245 of them were not smoking.

Assuming it is reasonable to regard this sample as representative of all smokers, estimate the percentage of all smokers who, when given this treatment, would refrain from smoking for at least 6 months.

This percentage is 245/935 = 0.2620.

26% of smokers,when given this treatment, would refrain from smoking for at least 6 months.

7 0
3 years ago
Use the functions f(x)=2x and g(x)=x^2+1 to find the value of each expression
Alinara [238K]

Answer:

1.  20

2. 23

3. 6

Step-by-step explanation:

We have that:

f(x) = 2x

g(x) = x² + 1

f(g(x)) is the composite function of f and g. So

f(g(x)) = f(x²-1) = 2(x²+1) = 2x² + 2

1. f(g(3))

f(g(x)) = 2x² - 2 = 2(3)² + 2 = 18 + 2 = 20

2. f(3)+g(4)

f(3) = 2(3) = 6

g(4) = 4² + 1 = 17

f(3) + g(4) = 6 + 17 = 23

3. f(5) - 2g(1)​

f(5) = 2(5) = 10

g(1) = (1)² + 1 = 2

f(5) - 2g(1) = 10 - 2*2 = 10 - 4 = 6

6 0
3 years ago
I need help with number 3 .
djverab [1.8K]

Answer:

there are 6 activities therefore 360/6 = 60 minutes on each activity

Step-by-step explanation:

5 0
3 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
3 years ago
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