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Lelechka [254]
3 years ago
15

Which of the following is an equation of a line parallel to the equation y = 1x +1? 2 O A. y = -2x-5 O B. y = 2x-5 2. C. y=-1X-5

C. y=- O D. y = 12 x - 5​
Mathematics
1 answer:
Alex777 [14]3 years ago
4 0

Answer:  B. y = 2x-5  is your answer hope this helped

plz make brainly

Step-by-step explanation:

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The magnitude and direction of two vectors are shown in the diagram. What is the magnitude of their sum? ​
VLD [36.1K]

Separate the vectors into their <em>x</em>- and <em>y</em>-components. Let <em>u</em> be the vector on the right and <em>v</em> the vector on the left, so that

<em>u</em> = 4 cos(45°) <em>x</em> + 4 sin(45°) <em>y</em>

<em>v</em> = 2 cos(135°) <em>x</em> + 2 sin(135°) <em>y</em>

where <em>x</em> and <em>y</em> denote the unit vectors in the <em>x</em> and <em>y</em> directions.

Then the sum is

<em>u</em> + <em>v</em> = (4 cos(45°) + 2 cos(135°)) <em>x</em> + (4 sin(45°) + 2 sin(135°)) <em>y</em>

and its magnitude is

||<em>u</em> + <em>v</em>|| = √((4 cos(45°) + 2 cos(135°))² + (4 sin(45°) + 2 sin(135°))²)

… = √(16 cos²(45°) + 16 cos(45°) cos(135°) + 4 cos²(135°) + 16 sin²(45°) + 16 sin(45°) sin(135°) + 4 sin²(135°))

… = √(16 (cos²(45°) + sin²(45°)) + 16 (cos(45°) cos(135°) + sin(45°) sin(135°)) + 4 (cos²(135°) + sin²(135°)))

… = √(16 + 16 cos(135° - 45°) + 4)

… = √(20 + 16 cos(90°))

… = √20 = 2√5

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3 years ago
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WITCHER [35]

Answer:

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3 years ago
The difference between two same-side interior angles of two parallel lines is 35 degrees. Find the measures of these two angles.
Leona [35]

Answer:

angle 1:    72.5°

angle 2:   107.5°

Step-by-step explanation:

x + y = 180

x - y = 35         ===>      x = 35 + y

Substitution to find angle y:

  x + y = 180

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Substitution to find angle x:

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ANSWER FOR BRAINLIEST AND 50 POINTS:
Elan Coil [88]

Answer:

A.

mean=82.286

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576 now will be divided by how many temperatures are recorded.

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