An = a1+d*(n-1)
a11 = 75-8*(11-1) = -5
We know that two complements add up to 90.
Let's call the smaller angle x and the larger y.
3x = y
x + y = 90
We can use simple substitution.
x + 3x = 90
4x = 90
x = 22.5
Then, since we know that 3x=y, we can find the larger angle.
3*22.5 = 67.5
I’m not really sure but I would say c
Answer:
x^3+6x^2+11x+12
Step-by-step explanation:
(x+4)(x^2+2x+3)
=x(x^2+2x+3)+4(x^2+2x+3) [by multiplying with bith sides]
=x^3+2x^2+3x+4x^2+8x+12
=x^3+2x^2+4x^2+3x+8x+12
=x^3+6x^2+11x+12
(please mark me brainliest)
Area covered by the solar cells = 269.5 m^2
Area of one cell = 150 cm^2
Convert the area of one cell to m^2 by using the conversion factor 1m^2 = (100cm)^2 => 1 = 1m^2 / 1000 cm^2
=> 150 cm^2 * [1m^2 / 1000 cm^2] = 0.150 m^2
Now finf the number of times that 0.150 is contained in 269.5 by dividing 269.5 by 0.150
269.5 = 0.150 = 1,796.67
Which means that the number of cells is betwee 1796 and 1797.
