The z-score of a certain data point in the given statistical data is calculated through the equation,
z-score = (x - m) / sd
where x is the data point, m is the mean and sd is the standard deviation.
Substituting the known values,
z-score = (51.8 - 52.3) / 1.8
z-score = -0.277
Rounding the answer to the nearest tenth will give an answer of -0.3.
To answer this question you would need to solve this inequality. The first step would be to combine all three terms on the left-hand side of the greater than symbol. By doing this you would have 50w > 250. To solve this inequality divide both sides by 50. The answer is w > 5. In words, this means the number of walnuts per spoonful is greater than five.
Well, 1/3 = 428 so that you could get the same thing as 28 75 hours for you to go to school
Given that mean of quiz scores = 6.4 and standard deviation = 0.7
And we need to use Chebyshev's theorem to find the range in which 88.9% of data will reside.
Chebyshev's theorem states that "Specifically, no more than
of the distribution's values can be more than k standard deviations away from the mean".
That is 


k = 3
So, we want the range of values within 3 standard deviations of mean.
Hence range is [mean -3*standard deviation, mean +3*standard deviation]
= [6.4 - 3*0.7 , 6.4+3*0.7]
= [6.4 - 2.1 , 6.4+2.1] = [4.3,8.5]