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4 years ago

If MNO IS NMO what statement best describes triangle MON?

Mathematics

2 answers:

ivolga24 [154]4 years ago

6 0

In a triangle MON, the two angles angle M and angle N are said to be equal single we know angle MNO = angle NMO.

As per the theorem in geometry, "Sides Opposite to Equal Angles of a Triangle are Equal". Therefore, when two angles of a triangle are equal, the sides that are opposite to them are also equal.

So, here we get a triangle with two equal sides which we call an isosceles triangle

Therefore, triangle MON is an isosceles triangle

kirill [66]4 years ago

5 0

If , what statement best describes triangle MON?

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If Sara saved 10% on a $60.00 blouse how much did she save

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3 years ago

Find the slope of the line that passes through (4.4) and (5,3)

Vera_Pavlovna [14]

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3 years ago

Help me please

Andreyy89

Answers:

Part (a) upper bound for area = 4527.7056 square cm
Part (b) lower bound for perimeter = 278 cm

======================================================

Explanation:

Part (a)

The horizontal portion is shown to be 87.3 cm long. This is the result after rounding has occurred. Specifically, rounding to one decimal place (tenths). The question is: What could the number have been before rounding?

You have to think in reverse of the usual rounding process.

The values 87.25, 87.26, 8.27, ... 8.33, 87.34 all round to 87.3 when we round to one decimal digit. Note the hundredths digit is increasing by 1 each time. We can see that 87.34 is the largest possible value for the horizontal piece. After that, 87.35 will round to 87.4 which is just out of reach.

Through similar logic/reasoning, the vertical side can be at most 51.84 cm.

The area of the rectangle could be 87.34*51.84 = 4527.7056 which is the upper bound for the area. This is the largest possible area, given the values in the diagram, since we made each value as large as possible.

In short, 4527.7056 square cm is the max area.

-----------------------------------

Part (b)

We use the idea of part (a), but we'll use the smallest possible values this time.

So we go with 87.25 for the horizontal portion and 51.75 for the vertical portion.

Compute the perimeter with these smallest dimensions.

P = 2*(length + width)

P = 2*(87.25 + 51.75)

P = 278

The smallest perimeter possible is 278 cm which is the lower bound of the perimeter. This is guaranteed to be the smallest perimeter possible because we made the sides as small as possible, while staying in the restrictions as discussed in the previous section.

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3 years ago

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Marta_Voda [28]

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