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yulyashka [42]
3 years ago
6

Jason has 43 stamps. Some

Mathematics
1 answer:
sveticcg [70]3 years ago
5 0

Jason has a total of 43 stamps, and we have two different stamps involved.

x = 15 cents

y = 20 cents

We will need to set up two equations and then use substitution:

43 = x + y (represents total stamps)

7.50 = 0.15x + 0.20y (represents total value)

To use substitution, we'll use the first equation and get either x or y on its own. In this case I will choose to get y on its own:

43 - x = x - x + y (subtract x to get y alone)

43 - x = y

Now we will use this in the second equation and simplify:

7.50 = 0.15x + 0.20(43 - x)

7.50 = 0.15x + 8.6 - 0.20x

7.50 = 8.6 - 0.05x

-1.1 = -0.05x (divide by -1.1 to get x alone)

22 = x

Now that we know Jason has 22 of the stamps that are worth 15 cents, we need to find y by plugging x, 22, into the first equation:

43 = 22 + y

21 = y

Jason has 22 stamps that are worth 15 cents and 21 stamps that are worth 20 cents.

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Answer:

The answer is below

Step-by-step explanation:

A parallelogram is a quadrilateral (has 4 sides and 4 angle) with two pair of parallel and opposite sides. Opposite sides of a parallelogram are parallel and equal.

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AB = CD = 18 cm; BC = AD = 8 cm

∠P = ∠P, ∠PDA = ∠PCQ (corresponding angles are equal).

Hence ΔPCQ and ΔPDA are similar by angle-angle similarity theorem. For similar triangles, the ratio of their corresponding sides equal. Therefore:

\frac{CD}{PC}= \frac{AD}{CQ}\\\\\frac{18}{6}=\frac{8}{x}  \\\\x=\frac{6*8}{18}=\frac{8}{3}\ cm

Perimeter of CPQ = CP + CQ + PQ

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PQ = 15 - (6 + 8/3)

PQ = 6.33

∠CQP = ∠AQB (vertical angles), ∠QCP = ∠QBA (alternate angles are equal).

Hence ΔCPQ and ΔABQ are similar by angle-angle similarity theorem

\frac{AQ}{QP}=\frac{AB}{CP}  \\\\\frac{AQ}{6.33} =\frac{18}{6} \\\\AQ=\frac{18}{6}*6.33\\\\AQ = 19

\frac{BQ}{CQ}=\frac{AB}{CP}  \\\\\frac{BQ}{8/3} =\frac{18}{6} \\\\BQ=\frac{18}{6}*\frac{8}{3} \\\\BQ =8

Perimeter of BAQ = AB + BQ + AQ = 18 + 8 + 19 = 45cm

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PD = CD + DP = 18 + 6 = 24

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Let's simplify step-by-step To understand :)

3x2−7x−(x2+3x−9)

Distribute the Negative Sign:

=3x2−7x+−1(x2+3x−9)

=3x2+−7x+−1x2+−1(3x)+(−1)(−9)

=3x2+−7x+−x2+−3x+9

Combine Like Terms:)

=3x2+−7x+−x2+−3x+9

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=2x2+−10x+9

Answer :)

=2x2−10x+9


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