-5(x+7)<-10.
You need to use the distributive property.
-5x - 35 < -10.
You need to cancel out -35, so you add it to itself, & -10.
-5x < 25.
You need to divide -5 by itself & 25.
x>-5.
By definition, if :


<span>We highlight the following elements:
</span><span>a = Base of the logarithm;
b = logarithmand or antilogarithm
y = logarithm</span><span>
Therefore:
</span><span>Note that since the base was not specified, we know that it is equal to 10.
</span>



<span>
Answer:
</span>
Base of the logarithm = 10
First, make 6 1/3 a improper fraction:

. Now we have 19/3*7/3:

.
Answer:
given
p=q^3
p=40
______
q=(p)^1/3
q=(40)^1/3-->q=2(5)^1/3
Now
the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.
finally the value of p gonna be
p=q^3
p=(5^1/3) ^ 3
p=5