I can see that the equation given above is a linear equation since y and x are the only variable and the degree is one. The standard form of a linear equation is written as:
Ax + By = C
We write the given equation into standard form as follows:
<span>y - 2 = 2(x - 3)
</span><span>y - 2 = 2x - 6
y -2x = -6 +2
y - 2x = -4
2x - y = 4</span>
Answer: IX - 4I ≤ 4
Step-by-step explanation:
In the numer line we can see that our possible values of x are in the range:
0 ≤ x ≤ 8
And we want to find an absolute value equation such that this set is the set of possible solutions.
An example can be:
IX - 4I ≤ 4
To construct this, we first find the midpoint M of our set, in this case is 4.
Then we write:
Ix - MI ≤ IMI
Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the < > signs.
Answer:
h(3) = - 140
Step-by-step explanation:
Generate the terms in the sequence by substituting n = 2 and 3 into h(n)
h(2) = h(2 - 1) × 2 = h(1) × 2 = - 35 × 2 = - 70
h(3) = h(3 - 1) × 2 = h(2) × 2 = - 70 × 2 = - 140
6+4• (5-7)^2
(5-7)^2
-2^2
4
6+4+4
=14
