Question

Suppose you perform a monohybrid cross of two pea plants. the plants are heterozygous at the locus for stem height. t is dominant to t. t confers tall plant height. when you count the progeny, you find that there are 188 tall plants and 62 short plants. does this approximate the 3:1 phenotypic ratio caused by mendelian inheritance?
a.no, you would expect there to be more short plants.

b.yes, there are approximately 3 short plants for every tall plant.

c.no, the number of each phenotype is not in the exact ratio of 3:1.

d.yes, there are approximately 3 tall plants for every short plant. submit for grading save and finish later

Answer 1

If T is the dominant allele and expresses the tall phenotype and t is recessive allele for short plants.
The parents are heterozygous Tt
cross between parents         
                 Tt        x         Tt
offspring  TT  Tt  tT   tt
tall plants - TT, Tt and tT - 75%
short plants - tt - 25%
ratio of tall plants to short plants - 0.75 :0.25 
0.75/0.25 = 3
In the cross performed , 188 tall : 62 short 
188/62 = 3.03
the obtained results follow the 3:1 phenotypic ratio approximately.
answer is b.yes, there are approximately 3 short plants for every tall plant.