one half hour past midnight is 1:00
one o clock
Given pair of lines are x² + 4xy + y² = 0
⇒ (y/x) ² + 4 y/x + 1 = 0
⇒ y/x = -4±2√3/2 = -2±√3,
∴ The lines y = (-2 + √3) x and y = (-2 - √3) x and x - y = 4 forms an equilateral triangle
Clearly the pair of lines x² + 4xy +y² = 0 intersect at origin,
The perpendicular distance form origin to x - y = 4 is the height of the
h = 2 √ 2
∵ Area of triangle = h²/√3 = 8/√3
Answer:5
Step-by-step explanation:5/3 x 3/1= 15/3= 5
I agree with the 14x all right, but the remainder of the other part is 178. I'm going to recheck my answer. I'm not confident about using synthetic division for this question. It is 57 years since I did something like this. If I was more confident, I would list the results of synthetic division because it is much easier to show than long division. I'm saying the answer should be 14x + 178.
It would be 8 because 8+4=12
