The standard form of the equation of a parabola is y= x2 - 8x + 29.
1 answer:
Answer:
A
Step-by-step explanation:
Put brackets around the first two tems.
y = (x^2 - 8x) + 29
Take 1/2 coefficient of the linear term -8. Square that result. Add it inside the brackets.
1/2 (- 8) = - 4
(- 4)^2 = 16
y = (x^2 - 8x + 16) + 29
Subtract 16 outside the brackets.
y = (x^2 - 8x + 16) + 29 - 16
Do the subtraction
y = (x^2 - 8x + 16) + 13
Represent what is inside the brackets as a square.
y = ( x - 4)^2 + 13
The answer is A
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No
The first one because it goes through pretty much all the points on the graph.