3 years ago

How many possible solutions could f(x) = 6x^3 + 8x^2 - 7x -3 have?

Mathematics

2 answers:

Alex17521 [72]3 years ago

3 0

3 possible solutions.

The reason is because of the degree, which is 3

Firlakuza [10]3 years ago

3 0

Answer:

( 3x + 1 ) × ( 2x^2 + 2x - 3 )

Step-by-step explanation:

= 6x^3 + 2x^2 + 6x +2x - 9x - 3

= 2x^2 × ( 3x +1 ) + 2x × ( 3x + 1 ) - 3 ( 3x + 1 )

= ( 3x + 1 ) × ( 2x^2 + 2x - 3 )

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oee [108]

Answer:

$\frac{1}{81}$

Step-by-step explanation:

Using the rule of exponents

$a^{-m}$ ⇔ $\frac{1}{a^{m} }$

Evaluating from the inside parenthesis outwards

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$(\frac{1}{9}) ^{-2}$ = $\frac{1}{9^{-2} }$ = 9² = 81 , then

$(81)^{-1}$ = $\frac{1}{81}$

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3 years ago

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3 years ago

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PilotLPTM [1.2K]

Answer:

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Step-by-step explanation:

3 0

2 years ago

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wlad13 [49]

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3 0

3 years ago

What is the value of x in the equation 2x+7=1

Lesechka [4]

First....we need to do inverse operation

Subtract 7 from both sides.

2x+7=1
-7 -7

2x=-6

Now, we need to divide 2 by both sides to isolate x.

2x=-6
2x/2=-6/2
x=-3

Our final answer is that x= -3

3 0

3 years ago

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