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umka2103 [35]
3 years ago
5

How many possible solutions could f(x) = 6x^3 + 8x^2 - 7x -3 have?

Mathematics
2 answers:
Alex17521 [72]3 years ago
3 0
3 possible solutions.


The reason is because of the degree, which is 3
Firlakuza [10]3 years ago
3 0

Answer:

( 3x + 1 ) × ( 2x^2 + 2x - 3 )

Step-by-step explanation:

= 6x^3 + 2x^2 + 6x +2x - 9x - 3

= 2x^2 × ( 3x +1 ) + 2x × ( 3x + 1 ) - 3 ( 3x + 1 )

= ( 3x + 1 ) × ( 2x^2 + 2x - 3 )

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What is the sum or whatever of this equation. This equation is V = πx3^2x8
navik [9.2K]

Answer:

V=226.08

Step-by-step explanation:

To evaluate V from the following expression:

V=\pi\times3^2\times 8

Taking \pi=3.14

V=3.14\times 3^2\times 8

V=3.14\times 9\times 8

∴ V=226.08

6 0
3 years ago
A bag contains 4 white, 2 blue, and
7nadin3 [17]

Answer:

1/2 for red

2/3

b+w=1/2

r+w=5/6

Step-by-step explanation:

3 0
3 years ago
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What number must you add to -6 to get a sum of zero? Explain
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3 years ago
What process is used to convert a percent to a fraction?
GalinKa [24]
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3 0
3 years ago
Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
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