The base of a triangle is 7 cm greater than the height. the area is 60 cm squared. find the height and base of the triangle.
2 answers:
Base=x+7 Height=x Area=60. 60=((x+7)(x))/2----->60=(x^2+7x)/2
120=x^2+7x X^2+7X-120=0. QUDRATIC FORMULA: -7+/- SQRT(49+480)/2
(-7+/-23)/2... 8 and -15. -15 ISNT the answer because you cant have a negative length. X=8 Base=8+7---->15 Height=8
Let height be x and the base will be x+7
so 1/2×b×h=60
= x(x+7)=120
x^2+7x-120=o
so...
solving the eqn .... x=8
therefore height =8 and base = 15 !
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hope this helps
I confused ! I don't get what your trying to say please explain better !