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Fudgin [204]
3 years ago
6

The base of a triangle is 7 cm greater than the height. the area is 60 cm squared. find the height and base of the triangle.

Mathematics
2 answers:
tino4ka555 [31]3 years ago
8 0
Base=x+7 Height=x Area=60. 60=((x+7)(x))/2----->60=(x^2+7x)/2

120=x^2+7x X^2+7X-120=0. QUDRATIC FORMULA: -7+/- SQRT(49+480)/2

(-7+/-23)/2... 8 and -15. -15 ISNT the answer because you cant have a negative length. X=8 Base=8+7---->15 Height=8
Julli [10]3 years ago
4 0
Let height be x and the base will be x+7

so 1/2×b×h=60
= x(x+7)=120
x^2+7x-120=o
so...
solving the eqn .... x=8

therefore height =8 and base = 15 !
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What is the net change in the temperature relative to when lko woke up
DedPeter [7]

Complete question:

Between the time iko woke up and lunchtime, the temperature rose by 11°. Then by the time he went to bed, the temperature dropped by 14°.

What is the net change in the temperature relative to when lko woke up?

Answer:

The net change in the temperature relative to when lko woke up =

\bold{-3} °

Step-by-step explanation:

Given that between his wake up time and lunch time, temperature rose by  11°. Let the new temperature be  \bold{T1} and let the initial temperature(temperature before wakeup time) be  \bold{T}

Since the temperature rose by 11°, the new temperature after Iko woke up, T1, would be derived by adding 11° to the initial temperature.

i.e,  T1 = T + 11......................(1)

At bed time the temperature dropped by 14°. Therefore, the temperature would now be 14 less than the new temperature T1. It is expressed as:

T1 + (-14).......................... (2)

Let's substitute T + 11 for T1 in equation 2, we have:

T + 11 + (-14)

To find the expression for the net change in temperature, let's subtract the initial temperature T, from (T+11 -14) i.e,

ΔT = (T + 11 - 14) - T

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ΔT = T - T + 11 - 14

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5 0
3 years ago
When 50 mL of water is added, the graduated cylinder has a mass of 180 g. If a rook is added to the graduated cylinder, the wate
Bezzdna [24]

Answer:

2.25 (or \frac{9}{4}) g/mL

<u>Skills needed: Density</u>

Step-by-step explanation:

1) Briefly, let's cover what density is:

- It is \frac{mass}{volume}

- Measures the mass per unit of volume

- In this situation the formula for density is: \frac{m_f-m_i}{v_f-v_i}

---> m_f is the final mass

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2) In this case, we start out with a mass of 180 grams as stated in the problem, and also 50 mL of water initially.

This means that:

- m_i is 180 g

- v_i is 50 mL

3) Also, we end up with 270 g in mass, and 90 mL of water finally.

- m_f is 270g

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4) We can find density by substitute given the values above:

\frac{270-180}{90-50} = \frac{90}{40} = \frac{9}{4} \text{ or } 2.25

5) Our answer is 2.25 g/mL (since mass is grams (g), and volume is milliliters (mL) in the problem above).

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3 years ago
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