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madreJ [45]
3 years ago
13

Y=1/3x-3 Y=-x+5 How do I solve

Mathematics
1 answer:
ehidna [41]3 years ago
4 0

Since both equations are equal to y, we can just combine them like this:

1/3x-3=-x+5

1/3x=-x+8

4/3x=8 (since x is 1x which is 3/3x)

x=6

Plug x back in:

y=-6+5

y=-1

So x=6 and y=-1

Hope this helped!

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Answer:

30 mins = 0.5 hours

4.5 miles/0.5 hours = your answer

Step-by-step explanation:

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2 years ago
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Read the question on the picture.
Marizza181 [45]

These two lines are congruent (the same) so we can set them equal to each other and solve.

5x-4=3x+6

The first thing we need to do is subtract 3x from both sides leaving us with 2x-4=6

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Now we need to divide both sides by 2 to get x alone.

Giving us our final answer of x=1

3 0
3 years ago
Let logb A= 3; logb C = 2; logb D=5<br> What is the value of logb D^2/C^3A
Ne4ueva [31]

Answer:

The value of given log function is 1 .

Step-by-step explanation:

Given as :

Logb A = 3

Logb C = 2

Logb D = 5

<u>Now from log property </u>

if , Logb x = c    , then  x = b^{c}

So,

Logb A = 3 , then A =  b^{3}

Logb C = 2 , then C =  b^{2}

Logb D = 5 , then D =  b^{5}

Now, According to question

Logb\frac{D^{2}}{C^{3}A}

So, Logb\frac{(b^{5})^{2}}{(b^{2})^{3}\times b^{3}}

Or, Logb\frac{b^{10}}{b^{6}\times b^{3}}

or, Logb\frac{b^{10}}{b^{9}}

Now, since base same So,

log_{b}b^{10-9}

∴ log_{b}b^{1}

<u>Now log property </u>

log_{b}b = 1

Hence The value of given log function is 1 . answer

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3 years ago
To enlarge or reduce a shape you must:
marta [7]
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2 years ago
Which function below is the inverse of f(x)= 7x-1/2
Keith_Richards [23]

Answer: f^{-1}(x)=\frac{x}{7}+\frac{1}{14}

Step-by-step explanation:

If we have y=7x-1/2, the inverse is where we solve for x instead of y.

We can isolate x to get 7x=y+1/2, then divide by 7 to get x=y/7+1/14.

Therefore, f^{-1}(x)=\frac{x}{7}+\frac{1}{14}.

Hope that helped,

-sirswagger21

8 0
3 years ago
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