Answer:
2(2 +5)
Step-by-step explanation:
We presume you want to rewrite the expression making use of the distributive property. For that, it is helpful to find a factor common to the two terms. The GCD of 4 and 10 is 2, so we can factor that out:
4 + 10 = 2(2 +5)
_____
Of course, you can use any factor you like. It doesn't need to be an integer.
= (1/3)(12 +30)
= 0.4(10 +25)
= 4(1 +2.5)
Answer:
<h2><em>
2ft by 2ft by 1 ft</em></h2>
Step-by-step explanation:
Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;
S = lw+2wh+2lh ... 1
Given the volume V = lwh = 4ft³ ... 2
From equation 2;
h = 4/lw
Substituting into r[equation 1;
S = lw + 2w(4/lw)+ 2l(4/lw)
S = lw+8/l+8/w
Differentiating the resulting equation with respect to w and l will give;
dS/dw = l + (-8w⁻²)
dS/dw = l - 8/w²
Similarly,
dS/dl = w + (-8l⁻²)
dS/dw = w - 8/l²
At turning point, ds/dw = 0 and ds/dl = 0
l - 8/w² = 0 and w - 8/l² = 0
l = 8/w² and w =8/l²
l = 8/(8/l² )²
l = 8/(64/I⁴)
l = 8*l⁴/64
l = l⁴/8
8l = l⁴
l³ = 8
l = ∛8
l = 2
Hence the length of the box is 2 feet
Substituting l = 2 into the function l = 8/w² to get the eidth w
2 = 8/w²
1 = 4/w²
w² = 4
w = 2 ft
width of the cardboard is 2 ft
Since Volume = lwh
4 = 2(2)h
4 = 4h
h = 1 ft
Height of the cardboard is 1 ft
<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>
All you do is multiply 60 * 40 = 2400 ft squared. you find area of a square by multiplying base * length. SO the answer is "D"
<span>It is cheaper for Tim to return the car on time and pay the refueling costs. If the gas tank on the car is half empty and the rental agency charges $4.50 per gallon the costs to refill for him would be. $27.00 plus the $5.00 refueling fee. This would equal $32.00. If Tim returns the car late, he faces a $32.00 charge including the cost to refuel the car on his own. The cost of returning the car a day late is not the same costs as returning the car on time. Choice b is the better option and the best choice.</span>
Answer:
4(4y - 3x)
16y -12x
you can't simplify this any further
