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lutik1710 [3]
3 years ago
13

what are the coordinates of the circumcenter of a triangle with vertices A(0,1) B(2,1) C(2,5)? PLEASE HELP

Mathematics
1 answer:
just olya [345]3 years ago
7 0
The answer to this is (1,3).
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Consider the polynomial p(x) = x^3 + 4x^2 + 6x − 36.
Nady [450]

Answer:

a. attached graph; zero real: 2

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Step-by-step explanation:

p(x) = x³ + 4x² + 6x - 36

a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.

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b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.

2 |  1     4     6    -36

     1      6    18     0

x² + 6x + 18 = 0

Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²

√Δ = 6i

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