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3 years ago

Filled in the box. The solution should be infinitely many solution

Mathematics

1 answer:

hichkok12 [17]3 years ago

4 0

Any real number meaning a number that doesnt have a decimal point behind it would be the correct answer in this cause due to the final answer being 7x=0

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HELP WILL GRIVE BRAIN 100 POINTS PLEASE ANSWER ALL 5

Stels [109]

Answer:

1. The sum of 4 and x is 7, and to isolate the variable, you move the 4 to the other side and the equation will change into x=7-4, giving us x = 3

2. To solve this inequality, you must isolate the variable x by moving -9 to the other side. To do this, you have to divide 27 by -9, and this causes the direction of the inequality sign to change. After you divide, the inequality changes to this: x<-3

3. since there are no negative numbers involved in this inequality, you divide 3 by 1/4 (or multiply it by 4) to isolate x. this gives us x <= -12

4. To solve this algebraic equation, you must isolate the variable 3x. To do this, you must move -9 to the other side of the equation by adding 9 to the 6. this gives us 3x=15 and x = 5

5. To put x by itself, you subtract 1 by 4, giving you x<-3

7 0

3 years ago

Read 2 more answers

Can you please solve thos type of question (Question 2)

densk [106]

Answer:

I hope it helped I guess we have to combine the like terms❤

3 0

3 years ago

Help I need the answer as soon as possible

pav-90 [236]

Answer:

Step-by-step explanation:

First, you multiply 18 1/4 with 10 1/2 and you get 191 5/8. Then you multiply 191 5/8 with 12 3/4 and you get D. 2443 7/32

3 0

2 years ago

Answer question worth 25 points plz help!

Ilya [14]

Answer:

Step-by-step explanation:

6 0

3 years ago

2 u + 12 < 23 0,1 d + 8 > 0 3 - 4 r > 7 13 < 2 z + 3 6 ≥ 9 - 0, 15 i

BartSMP [9]

Answer:

Part 1) $u< 5.5$

Part 2) $d > -80$

Part 3) $r < -1$

Part 4) $z>5$

Part 5) $i\geq 20$

Step-by-step explanation:

The question is

Solve each inequality for the indicated variable

Part 1) we have

$2u+12$

subtract 12 both sides

$2u< 23-12\\2u$

Divide by 2 both sides

$u< 5.5$

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

$0.1d+8 >0$

subtract 8 both sides

$0.1d > -8$

Divide by 0.1 both sides

$d > -80$

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

$3-4r> 7$

Subtract 3 both sides

$-4r>7-3\\-4r>4$

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$r < -1$

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

$13< 2z+3$

Subtract 3 both sides

$13-3$

Divide by 2 both sides

$5$

Rewrite

$z>5$

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

$6\geq 9-0.15i$

Subtract 9 both sides

$6-9\geq -0.15i\\-3\geq -0.15i$

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

$20\leq i$

Rewrite

$i\geq 20$

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0

3 years ago