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3 years ago

Filled in the box. The solution should be infinitely many solution

Mathematics

1 answer:

hichkok12 [17]3 years ago

4 0

Any real number meaning a number that doesnt have a decimal point behind it would be the correct answer in this cause due to the final answer being 7x=0

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LenKa [72]

THe answer is 36 BOI

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3 years ago

Write an equation in slope-intercept form of a linear function f whose graph satisfies the given conditions. The graph of f pass

IceJOKER [234]

F(x) = 5 is your answer

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3 years ago

Joyce has 41 feet of chicken wire. There is 5 times that length of chicken wire in the

Kipish [7]

Answer:

205

Step-by-step explanation:

41 multiplied by 5 = 205

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2 years ago

Graph the function y=2-VX+1. What is the missing x-coordinate for the point (x,- 1.24), to the nearest tenth?

alex41 [277]

8.4 dhndyshshsjsjs yup that’s it’s 778 it indicates

5 0

3 years ago

Read 2 more answers

Consider the functions f and g defined by \[f(x) = \sqrt{\dfrac{x+1}{x-1}}\qquad\qquad\text{and}\qquad\qquad g(x) = \dfrac{\sqrt

tino4ka555 [31]

Answer:

The given functions are not same because the domain of both functions are different.

Step-by-step explanation:

The given functions are

$f(x)= \sqrt{\dfrac{x+1}{x-1}}$

$g(x) = \dfrac{\sqrt{x+1}}{\sqrt{x-1}}$

First find the domain of both functions. Radicand can not be negative.

Domain of f(x):

$\dfrac{x+1}{x-1}>0$

This is possible if both numerator or denominator are either positive or negative.

Case 1: Both numerator or denominator are positive.

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

Case 2: Both numerator or denominator are negative.

$x+1\leq 0\Rightarrow x\leq -1$

$x-1\leq 0\Rightarrow x\leq 1$

So, the function is defined for x≤-1.

From case 1 and 2 the domain of the function f(x) is (-∞,-1]∪[1,∞).

Domain of g(x):

$x+1\geq 0\Rightarrow x\geq -1$

$x-1\geq 0\Rightarrow x\geq 1$

So, the function is defined for x≥1.

So, domain of g(x) is [1,∞).

Therefore, the given functions are not same because the domain of both functions are different.

4 0

3 years ago