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Varvara68 [4.7K]
3 years ago
10

Filled in the box. The solution should be infinitely many solution

Mathematics
1 answer:
hichkok12 [17]3 years ago
4 0
Any real number meaning a number that doesnt have a decimal point behind it would be the correct answer in this cause due to the final answer being 7x=0
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What is the greatest possible error when measuring to the nearest quarter of an inch
cestrela7 [59]
Using a scale that has increments that are somewhat large, you could get an error if you reach half of the measuring unit. This is because when you arrive at a measurement greater than half of the measuring unit, you would have to round it up. Therefore, the greatest possible error when measuring to the nearest quarter of an inch is 1/8 inch.                                                                The greatest possible error when measuring to the nearest quarter of an inch is how the reader reads the measurement. Sometimes, we base our answers to what we can see and what we see may be different from others. 
3 0
4 years ago
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What is the solution to<br> (y = 3x - 30<br> x2 + y2 = 100
PSYCHO15rus [73]

Answer:

x = 20

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Step-by-step explanation:

8 0
3 years ago
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Determine dois números ímpares consecutivo cujo produto seja 195
miv72 [106K]
Let 1st integer  = xLet 2nd integer = x + 1 We set up an equation. x(x + 1) = 195 x2 + x = 195 x2 + x - 195 = 0

We will use the quadratic formula: x = (-b ± √(b2 - 4ac) / (2a) x = (-1 ± √(1 - 4(-195))) / 2 x = (-1 ± √(781)) / 2 x = (-1 ± 27.95) / 2 x = 13.48x = -14.78 
<span>We determine which value of x when substituted gives us a product of 195.</span> 13.48(14.48) = 195.19-14.48(-13.48) = 195.19 <span>The solution is 2 sets of two consecutive number</span> <span>Set 1</span> The 1st consecutive integer is 13.48The 2nd consecutive integer is 14.48 
<span>Set 2</span> The 1st consecutive integer is -14.48The 2nd consecutive integer is -13.48Hopefully this helped, hard work lol :)
8 0
3 years ago
Someone please help ASAP
shtirl [24]

Answer:

{ \boxed{rational \: numbers}} \\  \frac{7}{16}  \\  \\  \sqrt{36}  =  \{6 \} \\  \\  \sqrt{81}  =  \{9 \}

{ \boxed{irrational \: numbers}} \\  \sqrt{120}  \\  \\  \sqrt{48}  \\  \\ \pi

4 0
3 years ago
Please HELP MEEEE IM SO CONFUSED
kumpel [21]

Answer:

we cant see the answers or the photo i sadly cant help

6 0
3 years ago
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