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Harlamova29_29 [7]
3 years ago
6

There are 275 people in a movie theater. Of those, 150 are adults. What is the ratio of

Mathematics
2 answers:
bonufazy [111]3 years ago
6 0

Answer:

children: adult= 5:6

Step-by-step explanation:

no. of children = total - adult

children = 125

ration = 125:150

= 5:6

Alexxandr [17]3 years ago
3 0

Answer:

270 to 150

Step-by-step explanation:

 

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Solve the inequality for 4(x+1)<-6
PIT_PIT [208]
Distribute
4x+4(less than) -6 

Subtract 4 on both side
4x(less than) -10

divide 4 both sides
x(less than)-2.5

(Final answer is bold) Good luck
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3 years ago
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Find the midpoint of the segment with the given endpoints (5,-9) and (-2,-2)
QveST [7]
Another way to solve this is to use the Midpoint Formula.  The midpoint of a segment joining points (x_1,y_1) and (x_2,y_2) is

\left(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2} \right)

So the midpoint of your segment is

\left(\frac{5+(-2)}{2},\frac{-9+(-2)}{2}\right) = \left(\frac{3}{2},-\frac{11}{2} \right)

Perhaps it helps to see that the x-coordinate of the midpoint is just the average of the x-coordinates of the points.  Ditto for the y-coordinate of the midpoint; just average the y's.
6 0
3 years ago
The ratio of girls to boys in grade 6 was 3:2 at Lincoln middle school last year. There were 60 kids in grade 6. How many in gra
olasank [31]

Answer:

40 girls 20 boys i think / guess

Step-by-step explanation:

3 0
3 years ago
• A researcher claims that less than 40% of U.S. cell phone owners use their phone for most of their online browsing. In a rando
antiseptic1488 [7]

Answer:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p > α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

Z = - 1.84

From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

8 0
3 years ago
Alyssa has 50 quarters and dimes. She has a total of $9.80. How many dimes does she have? Explain your steps.
Debora [2.8K]

Answer:

t $9.50 of it is quarters and 30 cents of it is dimes so 3 dimes

Step-by-step explanation:

8 0
2 years ago
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