Answer:
26.2 units
Step-by-step explanation:
We are given the points/vertices
A(6, 3),
B(6, - 2) , and
C(- 4, 3)
Step two
Let us find the distances between the given points/vertices
A-B =A(6, 3) to B(6,-2)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6-6)²+(-2-3)²)
d=√(-2-3)²)
d=√(-5)²)
d=5 units
B-C=B(6, - 2) to C(-4, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((-4-6)²+(3+2)²)
d=√(-10)²+(5)²)
d=√100+25
d=√125
d=11.2 units
C-A=C(-4, 3) to A(6, 3)
d=√((x2-x1)²+(y2-y1)²)
Substitute
d=√((6+4)²+(3-3)²)
d=√(10)²
d=√100
d=10 units
Hence the perimeter is 5+11.2+10
P=26.2 units
1) First is an odd function because f(-x)=-f(x)
3) 3d is an even function because f(-x)=f(x)
2) 2d looks like sin function and it is also odd.
Answer:
y=5/7 x=31/7
Step-by-step explanation:
Make the x values the opposite of each other:
-2(x+5y=8)
-2x-10y=-16
2x+3y=9
Combine like terms and solve for y:
-7y=-5
y=5/7
Plug y in to find x.
x+5(5/7)=8
x+25/7=8
56/7-25/7=x
x=31/7
<span>RT, i.e. is S the midpoint of RT? If it does, then RS = ST; RT = RS + ST; RT = 2 * RS; RT = 5 1/4</span>
I think it’s 2/7=8/28 1/4=7/28
