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2 years ago

What are the solutions to the system of equations? y = 2x^2 - 4x + 1 and y = 4x + 1. ( □, □) and (□,□).

Mathematics

1 answer:

Akimi4 [234]2 years ago

5 0

Answer:

(0, 1)

(4, 17)

Step-by-step explanation:

2x^2 - 4x + 1 = 4x + 1

2x^2 - 8x = 0

x(2x - 8) = 0

therefore either

x = 0

2x - 8 = 0

2x = 8

x = 4

(0, 1)

(4, 17)

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What are the solutions to the system of equations? y = 2x^2 - 4x + 1 and y = 4x + 1. ( □, □) and (□,□)​.

What are the solutions to the system of equations? y = 2x^2 - 4x + 1 and y = 4x + 1. ( □, □) and (□,□).