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Bad White [126]
3 years ago
14

Helpppppppp geometry. ill give 11 points

Mathematics
1 answer:
stiv31 [10]3 years ago
7 0

Answer:

98

Step-by-step explanation:

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Use lagrange multipliers to find the maximum and minimum values of the function subject to the given constraint. f(x,y = xyz; x^
Snezhnost [94]
I'm assuming the constraint involves some plus signs that aren't appearing for some reason, so that you're finding the extrema subject to x^2+2y^2+3z^2=96.

Set f(x,y,z)=xyz and g(x,y,z)=x^2+2y^2+3z^2-96, so that the Lagrangian is

L(x,y,z,\lambda)=xyz+\lambda(x^2+2y^2+3z^2-96)

Take the partial derivatives and set them equal to zero.

\begin{cases}L_x=yz+2\lambda x=0\\L_y=xz+4\lambda y=0\\L_z=xy+6\lambda z=0\\L_\lambda=x^2+2y^2+3z^2-96=0\end{cases}

One way to find the possible critical points is to multiply the first three equations by the variable that is missing in the first term and dividing by 2. This gives

\begin{cases}\dfrac{xyz}2+\lambda x^2=0\\\\\dfrac{xyz}2+2\lambda y^2=0\\\\\dfrac{xyz}2+3\lambda z^2=0\\\\x^2+2y^2+3y^2=96\end{cases}

So by adding the first three equations together, you end up with

\dfrac32xyz+\lambda(x^2+2y^2+3z^2)=0

and the fourth equation allows you to write

\dfrac32xyz+96\lambda=0\implies \dfrac{xyz}2=-32\lambda

Now, substituting this into the first three equations in the most recent system yields

\begin{cases}-32\lambda+\lambda x^2=0\\-32\lambda+2\lambda y^2=0\\-32\lambda+3\lambda z^2=0\end{cases}\implies\begin{cases}x=\pm4\sqrt2\\y=\pm4\\z=\pm4\sqrt{\dfrac23}\end{cases}

So we found a grand total of 8 possible critical points. Evaluating f(x,y,z)=xyz at each of these points, you find that f(x,y,z) attains a maximum value of \dfrac{128}{\sqrt3} whenever exactly none or two of the critical points' coordinates are negative (four cases of this), and a minimum value of -\dfrac{128}{\sqrt3} whenever exactly one or all of the critical points' coordinates are negative.
6 0
3 years ago
under the supremacy clause, can the states ignore federal laws? (its a yes or no question not a paragraph from g00gle)
djverab [1.8K]

Answer:

no

Step-by-step explanation:

no

4 0
3 years ago
Math help anyone please help! :)) will give brainliest
Mice21 [21]
1st find the slope m.
 m= (rise)/(run). Look up the graph and notice that the rise is 1 for a run =5
Then the slope will be 1/5
2 lines are parallel if they have the same slope so it's either 
 y= 1/5 x + 4 or 1/5 x + 12/5
our function is y = mx + b, but we know that m = 1/5
so the equation is y = 1/5 x + b
and we know that the function passes through the point (-2,2)
To calculate b, plug in y= 1/5 x + b , x & y by their respective values:
 2 = (1/5) (- 2) + b
2 = - 2/5 + b and b = 12/5, then the equation is Y= 1/5 X + 12/5
8 0
3 years ago
Solve 27 = 3^4x + 1? a) 1/4 b)1/2 c)2 d)4
Artemon [7]

Answer:

B

Step-by-step explanation:

27 = 3^3

3 = 4x + 1

2 = 4x

x = 1/2

5 0
4 years ago
Read 2 more answers
A vertical line has a(n) ________ slope. a. undefined b. negative c. zero d. positive
Olin [163]
C. Zero slope. If it's going straight up and down, there is no slope.
8 0
4 years ago
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